Question

*Urgent, will mark Brainliest Answer* I really need help with this, thank you!!

Answer 1

1.

The area of the circle is given by $\pi r^2$, so in your case it is $16\pi$ squared feet.

The whole center is given by a center angle of 360°, but you're only interested in the 152° sector.

So, we have the following proportion:

$360 \div \text{area of whole circle} = 152 \div \text{sector area}$

which means

$360 \div 16\pi = 152 \div x$

solving for x, we have

$x = \dfrac{2432\pi}{360} \approx 6.7 \pi$

2.

Given the center $(x_0,y_0)$ and the radius $r$, the equation of a circle is

$(x-x_0)^2+(y-y_0)^2 = r^2$

Plug your values to get

$(x-0)^2+(y-(-4))^2 = \sqrt{3}^2$

Which you can rewrite as

$x^2+(y+4)^2 = 3$

Or, if you prefer,

$x^2+y^2+8y+16 = 3 \iff x^2+y^2+8y+13 = 0$