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Shtirlitz [24]
3 years ago
12

2.27 is a terminating decimal true or false??

Mathematics
2 answers:
IRINA_888 [86]3 years ago
5 0

Answer:

true

Step-by-step explanation:

alina1380 [7]3 years ago
5 0

Answer:

The correct answer is True.

Step-by-step explanation:

  A terminating decimal, as the name implies, is a decimal that has an end.

The characteristic of these numbers is that their termination is with finite numbers of digits, in this case they are two numbers (27).

For a number to classify as terminating decimal it must also fulfill the function that can be transformed into a fraction and the number 2.27 fulfills it, being its fraction: \frac{227}{100}

Given this information, we can say that the answer is true.

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A because | | <- around a number means the absolute value which in this case is 6.

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3 years ago
Please Help<br> Given the function f(x)=x^2+2x+1, find:<br> f(2b)
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Answer:

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Step-by-step explanation:

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f(2b) = (2b)^2 +2(2b) +1

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3 years ago
Multiply the polynomials show steps
Karo-lina-s [1.5K]

Answer:

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Step-by-step explanation:

<u>When multiplying with two brackets, you need to multiply the three terms, (a²), (4a) and (-6) from the first bracket to all the terms in the second brackets, (3a²), (-a) and (3) individually. I have put each multiplied term in a bracket so it is easier.</u>

(a² + 4a - 6) × (3a² - a + 3) =

(a² × <em>3a²</em>) + {a² × <em>(-a)</em>} + (a² × <em>3</em>) + (4a × <em>3a²</em>) + {4a × <em>(-a)</em>} + (4a × <em>3</em>) + {(-6) × <em>a²</em>) + {(-6) × <em>(-a)</em>} + {(-6) × <em>3</em>}

<u>Now we can evaluate the terms in the brackets. </u>

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<u>We can open the brackets now. One plus and one minus makes a minus. </u>

3a^{4} + (-a³) + 3a² + 12a³ + (-4a²) + 12a + (-6a²) + 6a + (-18) =

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<u>Evaluate like terms.</u>

3a^{4} -a³ + 3a² + 12a³ -4a² + 12a -6a² + 6a -18 = 3a^{4} + 11a³ - 7a² + 18a - 18

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