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alukav5142 [94]
2 years ago
14

HURRY WILL MAKE BRAINLEST!! circle F is shown below. EB is a diameter and the radius is 3 units. Choose the correct

Mathematics
1 answer:
Yuki888 [10]2 years ago
3 0

Answer:

Arc length is equal to \theta r where \theta is the angle in radians and r is the radius.

Question 1:

\frac{\pi}{2}=\frac{\pi}{6}\times3

So the angle is CFD.

Question 2:

\pi=\frac{\pi}{3}\times3

So the angle is AFE.

Question 3:

2\pi=\frac{2\pi}{3}\times3

So the angle is AFB.

Question 4:

\frac{3\pi}{4}=\frac{\pi}{4}\times3

So the angle is BFC.

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Help me someone please
Andreas93 [3]

Answer:

150

Step-by-step explanation:

since a circle is 360 degrees, add up all of the other degrees and then subtract from 360

7 0
2 years ago
I’m confused and don’t have an angle tool to even try to do the question
yanalaym [24]
<h3>Answer:   40</h3>

=================================================

Explanation:

JQ is longer than QN. We can see this visually, but the rule for something like this is the segment from the vertex to the centroid is longer compared to the segment that spans from the centroid to the midpoint.

See the diagram below.

The ratio of these two lengths is 2:1, meaning that JQ is twice as long compared to QN. This is one property of the segments that form when we construct the centroid (recall that the centroid is the intersection of the medians)

We know that JN = 60

Let x = JQ and y = QN

The ratio of x to y is x/y and this is 2/1

x/y = 2/1

1*x = y*2

x = 2y

Now use the segment addition postulate

JQ + QN = JN

x + y = 60

2y + y = 60

3y = 60

y = 60/3

y = 20

QN = 20

JQ = 2*y = 2*QN = 2*20 = 40

--------------

We have

JQ = 40 and QN = 20

We see that JQ is twice as larger as QN and that JQ + QN is equal to 60.

7 0
3 years ago
Log (3x + 1) = 2<br><br> Solve the equation for X
elena-s [515]
The answer i got was 1/3
6 0
3 years ago
Read 2 more answers
Which equation is an identity?
Sav [38]

Answer:

Equation 3

Step-by-step explanation:

An identity is, simply put, an equation that is always true. 1 = 1, 2 = 2, and x = x are all examples of identities, as there's no case in which 1 ≠ 1, 2 ≠ 2, and x ≠ x. Essentially, if we can manipulate and equation so that we end up with the same value on either side, we've found an identity. Let's run through and try to solve each of these equations to see which one fulfills that condition:

8 - (6v + 7) = -6v - 1

8 - 6v - 7 = -6v - 1

1 - 6v = -6v - 1

1 = -1

This is clearly untrue. Moving on to the next equation:

5y + 5 = 5y - 6

5 = -6

Untrue again. Solving the third:

3w + 8 - w = 4w - 2(w - 4)

2w + 8 = 4w - 2w + 8

2w + 8 = 2w + 8

If we created a new variable z = 2w + 8, we could rewrite this equation as

z = z, <em>which is always true</em>. We can stop here, as we've now found that equation 3 is an identity.

4 0
3 years ago
Myerson borrowed $8,500 at 9% ordinary interest for 200 days. After 120 days, he made a partial payment of $4,000. What is the f
Lady_Fox [76]
Interest due at the end of 120 days
= 8500(120/365)(.09) = 251.51

so of his $4000 payment, $3748.49 will go towards reducing the debt.
so balance owing = 8500 - 3748.49
= 4751.51

interest for the remaining 80 days
= 4751.51(.09)(80/365) =93.73

total owing at the end = 4751.51+93.73
= $4845.23
3 0
2 years ago
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