AK = 640
Δ ABC and ΔFJK are similar. They are small triangles.
ΔCDF is the big triangle.
640 / 2 = 320 m= CF
AC & FK= 320/2 = 160 m each
2AC = CF = 2FK
2(160) = 320 = 2(160)
BG = 20 m
20/160 = x / 320
20*320 = 160x
6400 = 160x
6400/160 = x
40 = x
Area of CDF = (40 m * 320 m)/2 = 12,800 / 2= 6,400 m²
Answer:
opt B (2,0)
Step-by-step explanation:
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pls rate
Answer:
added cement = 200 kg
Step-by-step explanation:
Sand = 0.8*1400
Sand = 1120 kg
If 1120 kg of sand represents the total sand in the 8:2 mixture.
We have to create the equation of the 7:3 mixture as follows.
The sand amount continues the same but the total amount of the mixture and cement will change.
0.7*mixture_mass + 0.3*mixture_mass = mixture_mass
By replacing values, we have:
1120 kg + 0.3*(1400 kg + added cement)= 1400 kg + added cement
added cement = 200kg
Answer:
r = 1.4
Step-by-step explanation:
c = Pi * D
So c = 8.8 = Pi * D
So divide both sides by Pi
so 8.8 / Pi = 2.801 = D
Radius is half the Dimeter so divide 2.801 by 2 = 1.4