Answer:
range of f(x) = [-4, -2) ∪ [2, 8)
a+b+c+d = -4
Step-by-step explanation:
The graph is attached. The range is the vertical extent of the function. It is defined at f(0) = -4 and f(2) = 2.
The limits f(2-) and f(4-) are -2 and 8, respectively, so the graph has open circles there. These are the ends of the two half-open intervals that make up the range of the function.
The portion of the graph in the domain [4, 7) is included in the range [2, 8), so no special treatment is needed for that piece of the function.
Answer:
Step-by-step explanation:
Given
Required
Evaluate Blue when z = 9
To do this, we simply substitute 9 for z in
Convert indices to fraction
<em>Hence, the blue section has an area of </em>
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Answer:
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Step-by-step explanation:
We have to expand the powers of each of them:
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Answer:
π/8 radians
Step-by-step explanation:
THIS IS THE COMPLETE QUESTION
In 1 h the minute hand on a clock moves through a complete circle, and the hour hand moves through 1 12 of a circle. Through how many radians do the minute hand and the hour hand move between 1:00 p.m. and 1:45 p.m. (on the same day)?
SOLUTION
✓If the minute hand on a clock moves through complete circle in 1 hour, then it means that it goes through a circle and angle of circle in radians is 2π.
Between 1:00 p.m. and 1:45pm in the same day we have 45 minutes i.e (1.45 pm -1pm)
Within the 1hour minutes, the hand can move with complete cycle of 2π radians
Then At time t= 45minutes
Angle through the circle at 45 minutes= 45/60 ×2π radians
= 3π/2 radians
And if the hour hand goes through a complete cycle 1/12 as told in the question we have 1/2 × 2π radians
For t=45 minutes
Then 1/12 × 2π ×45/60
= π/8 radians
Hence, the minute hand and the hour hand move π/8 radians between 1:00 p.m. and 1:45 p.m.
V(x) = (2x - 3)/(5x + 4)
The domain is all Real numbers except x = -4/5, because if x = -4/5 the denominator would be zero and you cannot divide by zero.
{x | x ∈ R, x ≠ -4/5}
w(x) = (5x + 4)/(2x - 3)
similarly, x ≠ 3/2
so, {x| x ∈ R, x ≠ 3/2}
