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3 years ago

Find each angle measure

Mathematics

1 answer:

Burka [1]3 years ago

3 0

Step-by-step explanation:

m<AEC= 180-152= 28°

m<CEB= 180-28=152°

m<FEC= 90+28=118°

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I don't know how to do these sort of problems... Can someone help me out?

VLD [36.1K]

180=76+4x
180-76=4x
104=4x
104/4=x
26=x
Measurement A= 26

6 0

3 years ago

Ten members of the academic team went to a local restaurant after their contest. Each meal combo that came with soda cost $6.75,

Aneli [31]

Answer:

7 ordered with Soda;

3 ordered with water

Step-by-step explanation:

Given

$m \to$ With water

$n \to$ With Soda

So:

$m + n =10$ --- total

$5m + 6.75n = 62.25$ -- cost

Required

Find m and n

$m + n =10$

Make m the subject

$m = 10 - n$

Substitute $m = 10 - n$ in $5m + 6.75n = 62.25$

$5(10-n) +6.75n = 62.25$

$50-5n +6.75n = 62.25$

Collect like terms

$-5n +6.75n = 62.25 - 50$

$-5n +6.75n = 12.25$

$1.75n = 12.25$

Solve for n

$n = 12.25/1.75$

$n = 7$

$m = 10 - n$

$m = 10 - 7$

$m =3$

8 0

3 years ago

A veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses

Licemer1 [7]

Answer:

Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

Step-by-step explanation:

We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.

So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;

Z = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = average age of the random sample of horses with colic = 12 yrs

$\mu$ = average age of all horses seen at the veterinary clinic = 10 yrs

$\sigma$ = standard deviation of all horses coming to the veterinary clinic = 8 yrs

n = sample of horses = 60

So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P( $\bar X$ $\geq$ 12)

P( $\bar X$ $\geq$ 12) = P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ $\geq$ $\frac{12-10}{\frac{8}{\sqrt{60} } }$ ) = P(Z $\geq$ 1.94) = 1 - P(Z < 1.94)

= 1 - 0.97381 = 0.0262

Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

4 0

3 years ago

AB is tangent to circle O at B. What is the length of the radius r

steposvetlana [31]

check the picture below

Diane at your service :)

4 0

3 years ago

Help please? If you could answer both A and B that’d be great, but you can do only one if you want.

kati45 [8]

For a, this is just the median and the range of the data. Median is the middle number after all of them are in order, and the range is the highest number minus the smallest number.

If we arrange them all in order:

2, 4, 5, 5, 5, 6, 7, 8, 9, 9, 10, 10, 11, 12, 14, 15

The middle ones are 8 and 9, because there is an even number of results. That means the median is 8.5.

The range is 15 - 2, which is 13.

For b, 21 is an outlier because it is outside the set of movies watched. If 21 was a value in the table, that means that the order is:

2, 4, 5, 5, 5, 6, 7, 8, 9, 9, 10, 10, 11, 12, 14, 15, 21

Meaning that the middle value is now 9 (because of the odd number of values) and the range is 21 - 2, which is 19. The range would increase because the 21 is greater than all the other values (outlier), so the highest number is now 21. The median would also increase because you added a higher number to the list of numbers, so that the middle would shift one place higher.

Hope I helped!

5 0

3 years ago