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3 years ago

Answer pls i need help

Mathematics

1 answer:

nataly862011 [7]3 years ago

5 0

Answer:

What/where is the question you have for me?

Step-by-step explanation:

You might be interested in

Find the area using the given image.

8_murik_8 [283]

Answer:
54

Explanation:
Area of a triangle: 1/2 * base * height
1/2 * 18 * 6 = 54

Hope this helped you! :)

6 0

2 years ago

How does the value represented by the digit 4 in R compare to the value represented by the digit 4 in T?

timurjin [86]

Answer:

69x

Step-by-step explanation:

4 0

2 years ago

WHY IS THIS GETTING DELETED?? I NEED HELP

aliina [53]

If this exact question is repeatedly deleted, it's probably because of the ambiguity of the given equation. I see two likely interpretations, for instance:

$\dfrac{(5\times5)^k}{5^{-8}} = 5^3$

$\dfrac{5\times 5^k}{5^{-8}} = 5^3$

If the first one is what you intended, then

$\dfrac{(5\times5)^k}{5^{-8}} = \dfrac{(5^2)^k}{5^{-8}} = \dfrac{5^{2k}}{5^{-8}} = 5^{2k-(-8)} = 5^{2k+8} = 5^3$

and it follows that

2k + 8 = 3 ==> 2k = -5 ==> k = -5/2

If you meant the second one, then

$\dfrac{5\times 5^k}{5^{-8}} = \dfrac{5^1\times5^k}{5^{-8}} = \dfrac{5^{k+1}}{5^{-8}} = 5^{k+1-(-8)} = 5^{k+9} = 5^3$

which would give

k + 9 = 3 ==> k = -6

And for all I know, you might have meant some other alternative... When you can, you should include a picture of your problem.

3 0

3 years ago

Help me please I don’t know how to

Irina-Kira [14]

Answer:

A: 22

Step-by-step explanation:

2The interquartile range begins at 45 and ends at 67. All you need to do is subtract 45 drom 67, and you get 22.

4 0

2 years ago

The length of a rectangular room is 7.4m and it's width is 5.5m. Find the area of the room.

oee [108]

Area of a rectangle is
$length\times width$
(7.4×5.5)m
=40.7m
therefore the area of the room is 40.7m

7 0

3 years ago