The child's starting and finishing location is the same, therefore the displacementnis zero.
Answer:
Step-by-step explanation:
In order to combine like terms, you have to isolate x and y from one side of the equation.
<u>First, thing you do is remove parentheses.</u>
<u>Solve.</u>
<u>Then, you combine like terms.</u>
<u>Add/subtract the numbers from left to right.</u>
-8z+3.5z=-4.5z
<u>Rewrite the problem down.</u>
<u>Solve.</u>
4.5-1.5=3
- <u>Therefore, the correct answer is 7y+3-4.5z.</u>
I hope this helps, let me know if you have any questions.
Answer:
For the perfect square trinomial (quadratic) i.e. 
, the constant term (last term) is positive.
Step-by-step explanation:
"Perfect square trinomials" are termed as the quadratics that are the outcomes of squaring binomials.
For example:
Therefore, for the perfect square trinomial (quadratic) i.e. , the constant term (last term) is positive.
In this case all you do is add all the numbers, answer is 100
Answer:
D) 0 = 2(x + 5)(x + 3)
Step-by-step explanation:
Which of the following quadratic equations has no solution?
We have to solve the Quadratic equation for all the options in other to get a positive value as a solution for x.
A) 0 = −2(x − 5)2 + 3
0 = -2(x - 5) × 5
0 = (-2x + 10) × 5
0 = -10x + 50
10x = 50
x = 50/10
x = 5
Option A has a solution of 5
B) 0 = −2(x − 5)(x + 3)
Take each of the factors and equate them to zero
-2 = 0
= 0
x - 5 = 0
x = 5
x + 3 = 0
x = -3
Option B has a solution by one of its factors as a positive value of 5
C) 0 = 2(x − 5)2 + 3
0 = 2(x - 5) × 5
0 = (2x -10) × 5
0 = 10x -50
-10x = -50
x = -50/-10
x = 5
Option C has a solution of 5
D) 0 = 2(x + 5)(x + 3)
Take each of the factors and equate to zero
0 = 2
= 0
x + 5 = 0
x = -5
x + 3 = 0
x = -3
For option D, all the values of x are 0, or negative values of -5 and -3.
Therefore the Quadratic Equation for option D has no solution.
