Answer:
(0,1)
Step-by-step explanation:
The mid point of A(-2,2) and B(2,-4) is the coordinates of point P, which is (x,y)
Hence, the line AB = AP + PB.
At point AP: x = (-2+2)/2 = 0
also, point PB: y = (2 - 4)/2 = -1
Therefore, coordinates of point P = (0,-1)
E(3.75,-2.5)
G(-0.75,-3)
Point E is the midpoint of the segment AB, then it has coordinates
Point F is the midpoint of the segment EB, then it has coordinates
Let S be the midpoint of segment CB, then it has coordinates
Point G is the midpoint of segment CS, then its coordinates are
6(2y - 1) - 4y simplified is 8y-6
There is no graph