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Hoochie [10]
3 years ago
9

Solve each of the following unit rate problems using model drawings.

Mathematics
1 answer:
rodikova [14]3 years ago
6 0

Answer:

1

Explanation:

The recipe calls for every 1 cup of cream cheese there is a cup of ranch dressing. 1:1

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Write each vector described below in component form and find its magnitude. Draw an arrow originating from (0,0) to
ElenaW [278]

Answer:

a = 3xi - 4yj              b = -6xj      c = -2xi + 2yj  d = 5xi  + 7yj

a ; b ; c ; d vectors

i and j   unit vectors

Step-by-step explanation:

See attached file

8 0
3 years ago
Evaluate:<br><br> 16 - 12 + 13.5 - - 14
Oxana [17]

Answer:

31.5

Step-by-step explanation:

5 0
2 years ago
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What is the square root of –16?<br><br><br><br> –8i<br><br> –4i<br><br> 4i<br><br> 8i
Ad libitum [116K]

we know that

i^{2} =-1

we have

\sqrt{-16} =\sqrt{(-1)*(16)} =\sqrt{(-1)*(4^{2})}

substitute the value of i^{2}=-1 in the expression above

\sqrt{(-1)*(4^{2})}=\sqrt{i^{2}*4^{2}} \\ \\= 4i

therefore

<u>the answer is</u>

4i


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3 years ago
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B. The 3 is repeated in a function every x has exactly one y. Hope this helped !
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three hens lay 3 eggs any 3 days. in how many days will 3n hens lay at this rate 9nk eggs? please i need answer fast!!! will giv
dangina [55]

If three hens lay 3 eggs any 3 days. The number of days that 3 Hens give in 9 eggs is: 9days.

<h3>Number of days that three hens lay 9 eggs</h3>

Given:

3 hens lay 3 eggs in 3 days

First step is to determine the number of egg one hen lay in 3 days

1 hen in 3 days lays 3/3

1 hen in 3 days lays=1 egg

Second step is to determine the number of egg 3 hens lay 1 day

1 hen in 1 day lays 1/3 egg

3 hens in 1day lay=(1×3)/3

3 hens in 1day lay=1 egg

Third step is to determine the number of eggs 3 hens lay in 9 days

3 hens in 9 days lay=(1×9)

3 hens in 9 days lay=9 eggs

Therefore assuming three hens lay 3 eggs any 3 days. The number of days that 3 Hens give in 9 eggs is: 9days.

Learn more about number of days that three hens lay 9 eggs here: brainly.com/question/9286901

#SPJ1

7 0
1 year ago
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