<em>So</em><em> </em><em>the</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em> </em><em>X </em><em>is</em><em> </em><em>3</em><em> </em><em>and</em><em> </em><em>y</em><em> </em><em>is</em><em> </em><em>2</em><em>.</em>
<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>
<em>Hope </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em>
<h2>
<em>FOLLOW</em><em> </em><em>ME</em><em> </em><em>FOR</em><em> </em><em>MORE</em><em>.</em></h2>
<h3>
<em>-pragya~</em><em>~</em></h3>
<em> </em>
We are given : Distance of the swing = 100 feet.
Distance of slide = 80 feet.
Angle between swing and slide = 30 degrees.
We need to find the distance between the swing and the slide.
Distance of swing, distance of slide and distance between the swing and the slide form a triangle.
We can apply cosine law to find the distance between the swing and the slide.
c^2 = a^2 +b^2 - 2ab cos C
c^2 = 100^2 +80^2 - 2(100)(80) cos 30°
c^2 = 10000 + 6400 -2* 8000
c^2 = 16400 - 8000
c^2 = 16400 - 13856
c^2 = 2544
c= 50.44
c = 50 feet approximately.
<h3>Therefore, the approximate distance between the swing and the slide is 50 feet.</h3>
Answer:
20
Step-by-step explanation:
8×25 means that he got 5 wrong so he got 20 right