Answer:
a solid in a gas
Explaination:
because soild will take a long while to dissolve into liquid by heating the soild with gas it will disslove quicker
Explanation:
a material system in which mass or energy can be lost to or gained from the environment.
Molecular weight of vanillin = 152 g/mol
Futher molecular formula of vanillin is C8H8O3
Atomic weight of oxygen = 16 g/mol
Thus, 152 g of vanillin contains 16 g of oxygen
∴ 0.045 g (45 mg) of vanillin contains
= 0.00473 g
Also, number of moles of vanillin in 0.045 g sample =
Now, 1 mole = 6.023 X 10^23 molecules
∴ 2.96 X 10^-4 mole = 1.78 X 10^20 molecules
From molecular formula, it can be seen that 1 molecule of vanallin contain 3 atoms of oxygen
∴1.78 X 10^20 molecules contain 3 X 1.78 X 10^20 = 5.34 X 10^20 oxygen atoms
Answer:
Silicates are kind of inert reactively, it could be used as hydrocarbin additives, lubricants and much more.
Completing the Sentences;
1. Carbon
2. insulating
3. Good lubricant and electrically conductive
Explanation:
SiO2 has a peculiar nature. It isn't very reactive. It has a very high melting point. grinding wheels. It is difficult to deform or melt it and its related compounds because its polar covalent (Si–C or Si–O) bonds must be broken, and this requires a large input of energy. It also does not contain any hydrogen, thus it cannot act as a Brønsted–Lowry acid. While not soluble in water, it dissloves in hot concentrated alkali or fused hydroxide.
Silicon metal is made from the reaction of silica (silicon dioxide, SiO2) and carbon materials like coke, coal and wood chips. Silica is typically received in the form of metallurgical grade gravel.
Silicates can be used as solid lubricants, lubricant additives in engine oil, as fume silica grease, rubber materials, waterproofing materials, and caulks.
Fused Silica has extremely good dielectric and insulating properties. For these reasons it is used as an inert, low expansion filler material for epoxy resins in electronic circuits as an insulator.
From the information provided in the question, the mass of gold that can be obtained from this sample is 31.5 g of Au.
Given that the reduction of gold III occurs thus;
Au^3+(aq) + 3e ------> Au(s)
Number of moles of gold(III) chloride dihydrate = mass/molar mass = 54.9 g /339.35 g/mol = 0.16 moles
Number of moles of Au^3+ in AuCl3.2H20 = 0.16 moles
Now;
1 mole of Au has a mass of 197 g/mol
0.16 moles of Au has a mass of 0.16 moles × 197 g/mol/1 mole
= 31.5 g of Au.
The mass of gold that can be obtained from this sample is 31.5 g of Au.
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