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jolli1 [7]
3 years ago
7

A chemist wants to extract the gold from 54.9 g of AuCl3*2H20 *gold(III) chloride dyhydrate) by electrolysis of an aqueous solut

ion. What mass of gold could be obtained from this sample? Answer in units of g
Chemistry
1 answer:
Greeley [361]3 years ago
8 0

From the information provided in the question, the mass of gold that can be obtained from this sample is 31.5 g of Au.

Given that the reduction of gold III occurs thus;

Au^3+(aq) + 3e ------> Au(s)

Number of moles of gold(III) chloride dihydrate = mass/molar mass = 54.9 g /339.35 g/mol = 0.16 moles

Number of moles of Au^3+ in  AuCl3.2H20 =  0.16 moles

Now;

1 mole of Au has a mass of 197 g/mol

0.16 moles of Au has a mass of 0.16 moles ×  197 g/mol/1 mole

= 31.5 g of Au.

The mass of gold that can be obtained from this sample is 31.5 g of Au.

Learn more: brainly.com/question/6284546

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Answer:

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Explanation:

The radiative force that the Earth receives comes from the Sun. When the Sun rays come to the surface, some of them are absorbed and then it is reflected in the space. The greenhouse gases (like CO2) blocks some of these rays, and then the surface stays warm. The excessive amount of these gases makes the surface warmer, which unbalance the climate on Earth.

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