Answer:
T2 = 36.38°C
Explanation:
Given data:
Mass of water = 75 g
Initial temperature = 30 °C
Final temperature = ?
Heat absorbed = 2000 J
Solution:
Specific heat capacity of water is 4.18 J/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = Final temperature - initial temperature
2000 J = 75 g×4.18 J/g.°C × T2- T1
2000 J = 313.5 J/°C × T2- T1
2000 J = 313.5 J/°C × T2 - 30 °C
2000 J / 313.5 J/°C = T2 - 30 °C
6.38 °C = T2 - 30 °C
T2 = 6.38 °C + 30°C
T2 = 36.38°C
