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3 years ago

I need to know answer to the quest

Mathematics

2 answers:

Liono4ka [1.6K]3 years ago

6 0

Answer:

1 and 1/16 gallons

Step-by-step explanation:

stealth61 [152]3 years ago

3 0

1/1/16 that’s the answer

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HELPP PLS

aev [14]

Answer: 1/14

Solution:

1/2 + x = 4/7

4/7 - 1/2 = x

8/14 - 7/14 = 1/14

Check:

1/2 + 1/14 = 7/14 + 1/14 = 8/14 = 4/7

4 0

3 years ago

Convert the polar coordinates (3, -5 pi/3). to rectangular coordinates.

beks73 [17]

Answer:

See below

Step-by-step explanation:

x = 3 cos (-5pi/3) = 1.5

y = 3 sin (-5pi/3) = 2.598

6 0

2 years ago

Problem 1.(32 points) A random sample of 100 Uber rides in Chicago has on average 5.4miles per ride. Assume the distribution of

marshall27 [118]

Answer:

a) CI = ( 5,1 ; 5,7 )

b) SE = 0,1

Step-by-step explanation:

a) Sample random n = 100

Mean = μ = 5,4

Standard deviation s = 1,3

CI = 99 % α = 1 % α = 0,01 α/2 = 0,005

z(c) for 0,005 is from z-table z(c) = 2,575

z(c) = ( X - μ ) /s/√n CI = μ ± z(c) * s/√n

CI = 5,4 ± 2,575* 1,3/10

CI = 5,4 ± 0,334

CI = ( 5,1 ; 5,7 )

b) SE = Standard deviation / √n

SE = 1,3 /10 SE = 0,1

We can support that with 99 % of probability our random variable will be in the CI.

6 0

2 years ago

Q2 direct and indirect

alekssr [168]

Answer:

i dont understand sorry

4 0

3 years ago

The manager of a fleet of automobiles is testing two brands of radial tires and assigns one tire of each brand at random to the

Darya [45]

Answer:

Brand 1 Brand 2 Difference

37734 35202 2532

45299 41635 3664

36240 35500 740

32100 31950 150

37210 38015 −805

48360 47800 560

38200 37810 390

33500 33215 285

Sum of difference = 2532+ 3664+740+150 −805+ 560 +390 +285 = 7516

Mean = $d=\frac{7516}{8}$

Mean = $d=939.5$

a) d= 939.5

$\text{Sample Standard deviation, s} = \sqrt{\dfrac{(x-\bar{x})^2}{n-1}}$

$=\sqrt{\dfrac{(2532-939.5)^2+(3664-939.5)^2+(740-939.5)^2 ...+(285-939.5)^2}{8-1}}$

=1441.21

b)SD= 1441.21

c)Calculate a 99% two-sided confidence interval on the difference in mean life.

confidence level =99%

significance level =α= 0.01

Degree of freedom = n-1 = 8-1 =7

So, $t_{\frac{\alpha}{2}}=3.499$

Formula for confidence interval $= \left( \bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}} \right)$

Substitute the values

confidence interval $= 939.5 \pm 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$

confidence interval $= 939.5 - 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$ to $= 939.5 + 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$

Confidence interval $−843.396\$ to $2722.396$

8 0

3 years ago