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mario62 [17]
3 years ago
12

How to find the slope of points (03 , 4) and (3,-4) ?

Mathematics
1 answer:
alisha [4.7K]3 years ago
8 0

Answer:

You have to put it into this equation

Y2-Y1/X2-X1

So when it’s plugged in it’ll look like this

-4-3/3-0

That leads to -7/3

That’s your answer: -7/3 or in decimal form -2.333repeating

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Step-by-step explanation:

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Write the expression without the fraction bar.
kirill115 [55]
For problems like this you can move the y's on the bottem up top by fliping the sign of the exponent (in this case 7 to -7) and MULTIPLYING it with EVERYTHING on top, then because of properties of multplication you can add the exponents to combine them into one term (in this case add 3 and -7 to get -4) \frac{ y^{3} }{y^{7}}=y^3 *y^{-7} = y^{3+-7}=y^{3-7}=y^-4 If any of this does not make sense let me know and ill try to clarify better
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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s). The vertex of a
dolphi86 [110]
Vertex form:
y-k=a(x-h)^2
h=-2,k=-20,y=-12 when x=0
thus;
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Equation:
y+20=2(x+2)^2
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4 0
4 years ago
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How can i get answer 5 for -10 - (+5) ?​
timama [110]

Answer:

- 10 - (-20 + 5)

Step-by-step explanation:

- 10 - (-20 + 5)

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have a nice day and mark me brainliest! :)

4 0
3 years ago
A line joins the point
Harrizon [31]

Intersection of the first two lines:

\begin{cases}5x - 2y + 3 = 0\\4x - 3y + 1 = 0\end{cases}

Multiply the first equation by 4 and the second by 5:

\begin{cases}20x - 8y + 12 = 0\\20x - 15y + 5 = 0\end{cases}

Subtract the two equations:

(20x - 8y + 12)-(20x - 15y + 5)=0 \iff 7y+7=0 \iff y=-1

Plug this value for y in one of the equation, for example the first:

5x - 2\cdot (-1) + 3 = 0\iff 5x+5=0 \iff x=-1

So, the first point of intersection is (-1,-1)

We can find the intersection of the other two lines in the same way: we start with

\begin{cases}x=y\\x=3y+4\end{cases}

Use the fact that x and y are the same to rewrite the second equation as

x=3x+4 \iff 2x=-4 \iff x=-2

And since x and y are the same, the second point is (-2, -2)

So, we're looking for a line passing through (-1,-1) and (-2, -2). We may use the formula to find the equation of a line knowing two of its points, but in this case it is very clear that both points have the same coordinates, so the line must be y=x

In the attached figure, line 5x - 2y + 3 = 0 is light green, line 4x - 3y + 1 = 0 is dark green, and their intersection is point A.

Simiarly, line x=y is red, line x = 3y + 4 is orange, and their intersection is B.

As you can see, the line connecting A and B is the red line itself.

5 0
3 years ago
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