All categories

3 years ago

-q divided by -7>eqauls -1

Mathematics

1 answer:

kifflom [539]3 years ago

3 0

-q/-7≥-1
q/7≥-1
q≥-1*7
q≥-7

Solution: q≥-7 or q∈[-7,+∞).

You might be interested in

One square megameter is equal to 1.0×106 square kilometers. How many square megameters are in 9,000,000 square kilometers?

Firlakuza [10]

9, because one square megameter is equal to one million square kilometers.

7 0

3 years ago

Read 2 more answers

The difference of d minus 3 divided by 2?

Allisa [31]

$\text{Hey there!}$

$\text{What is the difference of d minus 3 divided by 2?}\\\\\text{Difference means subtract/subtraction}\\\\\text{Minus would also be subtraction}\\\\\text{Divided by is division}\\\\\text{d would be the start of the problem}\\\\\text{the 3 divided by 2 would be on the right side ( the second part of the equation)}\\\\\boxed{\boxed{\bf{\ Answer:: d-\dfrac{3}2{}}}}}\checkmark$

$\text{Good luck on your assignment and enjoy your day}\\\\\\\frak{LoveYourselfFirst:)}$

6 0

3 years ago

Evaluate the expression 4(2x + 3) + 2(x + 1)-7

Svetlanka [38]

4 (2x + 3) + 2 (x + 1) - 7

8x + 12 + 2x + 2 - 7

10x + 7

10x = -7
10x/10 = -7/10

x = -7/10

hope this helps

4 0

3 years ago

A juggler tosses a ball into the air . The balls height, h and time t seconds can be represented by the equation h(t)= -16t^2+40

malfutka [58]

PART A

The given equation is

$h(t) = - 16 {t}^{2} + 40t + 4$

In order to find the maximum height, we write the function in the vertex form.

We factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + 4$

We add and subtract

$- 16(- \frac{5}{4} )^{2}$

to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + - 16( - \frac{5}{4})^{2} - -16( - \frac{5}{4})^{2} + 4$

We again factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4})^{2} ) - -16( - \frac{5}{4})^{2} + 4$

This implies that,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4}) ^{2} ) + 16( \frac{25}{16}) + 4$

The quadratic trinomial above is a perfect square.

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +25+ 4$

This finally simplifies to,

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +29$

The vertex of this function is

$V( \frac{5}{4} ,29)$

The y-value of the vertex is the maximum value.

Therefore the maximum value is,

$29$

PART B

When the ball hits the ground,

$h(t) = 0$

This implies that,

$- 16 ( t- \frac{5}{4}) ^{2} +29 = 0$

We add -29 to both sides to get,

$- 16 ( t- \frac{5}{4}) ^{2} = - 29$

This implies that,

$( t- \frac{5}{4}) ^{2} = \frac{29}{16}$

$t- \frac{5}{4} = \pm \sqrt{ \frac{29}{16} }$

$t = \frac{5}{4} \pm \frac{ \sqrt{29} }{4}$

$t = \frac{ 5 + \sqrt{29} }{4} = 2.60$

or

$t = \frac{ 5 - \sqrt{29} }{4} = - 0.10$

Since time cannot be negative, we discard the negative value and pick,

$t = 2.60s$

8 0

3 years ago

$20 haircut with 10% and 7% tax

Anika [276]

20 * .10 = 2 <em>(2 = 10% of 20)</em>

20 + 2 = 22

20 x .07 = 1.4 <em>(1.4 = 7% of 20)</em>

20 + 1.4 = 21.4

The price of a 20$ haircut with a 10% tax would be $22.

The price of a 20$ haircut with a 7% tax would be $21.40.

4 0

3 years ago