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3 years ago

8

A rectangular prism is 2 meters long, 50 centimeters wide, and 1 meter high. What is its volume? (Hint: How many centimeters are

in a meter?)

1 answer:

Blizzard [7]3 years ago

7 0

200 cm long * 50 cm * 100 cm
= 1,000,000 cubic centimeters

You might be interested in

The stemplot displays the selling prices of homes for ABC Realty in April.

Alexxandr [17]

The stemplot displays the entire values for the selling prices of homes for ABC Reality in April.

The correct set of data for the stemplot is the option;

<u>$459,000, $227,000, $67,000, $123,000, $213,000, $482,000, $85,000, $181,000, $225,000, $92,000, $181,000, $287,000, $196,000, $276,000</u>

<h3>Method by which the above option is selected</h3>

The data in the stemplot are;

459,000, 482,000, 213,000, 225,000, 276,000, 277,000, 287,000, 123,000, 181,000, 181,000, 196,000, 67,000, 85,000, 92,000

Given that there are no values in the 300,000s, and that 181,000 appear twice, the option that corresponds to the above data is therefore;

$459,000, $277,000, $67,000, $123,000, $213,000, $482,000, $85,000, $181,000, $225,000, $92,000, $181,000, $287,000, $196,000, $276,000

Learn more about stemplot here:

brainly.com/question/10572086

6 0

2 years ago

How does replacing f(x) with f(x) + k, k f(x), f(kx), and f(x + k) for specific values of k (both positive and negative) affect

ivann1987 [24]

F(x) + k - Moves the graph k units up.

k f(x) stretches the graph parallel to y-axis by a facor k

f (kx) stretches the graph by a factor 1/k parallel to x-axis

f(x + k) moves the graph 3 units to the left.

For k negative the first one moves it k units down

for second transform negative does same transfoormation but also reflects the graph in the x axis

For the third transform negative k :- same as above but also reflects in y axis

4th transform - negative k moves graph k units to the right

4 0

3 years ago

Apply the distributive property and the greatest common factor to write an equivalent expression.

amid [387]

Here, Your Original expression is 60x - 24.

Take 12 as common, which is GCD of 24 & 60,

Therefore, It would be:

60x - 24
= 12 * 5x - 12 * 2
= 12 (5x - 2)

In short, your Answer would be 12(5x - 2)

Hope this helps!

Photon

5 0

3 years ago

Jenny and Natalie are selling cheesecakes for a school fundraiser. Customers can buy chocolate cakes and vanilla cakes. Jenny so

IrinaVladis [17]

The cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7

<em><u>Solution:</u></em>

Let "c" be the cost of 1 chocolate cake

Let "v" be the cost of 1 vanilla cake

<em><u>Jenny sold 14 chocolate cakes and 5 vanilla cakes for 119 dollars</u></em>

Therefore, we can frame a equation as:

14 x cost of 1 chocolate cake + 5 x cost of 1 vanilla cake = 119

$14 \times c + 5 \times v=119$

14c + 5v = 119 ------- eqn 1

<em><u>Natalie sold 10 chocolate cakes and 10 vanilla cakes for 130 dollars</u></em>

Therefore, we can frame a equation as:

10 x cost of 1 chocolate cake + 10 x cost of 1 vanilla cake = 130

$10 \times c + 10 \times v = 130$

10c + 10v = 130 -------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

Multiply eqn 1 by 2

28c + 10v = 238 ------ eqn 3

<em><u>Subtract eqn 2 from eqn 3</u></em>

28c + 10v = 238

10c + 10v = 130

( - ) --------------------------

18c = 108

c = 6

<em><u>Substitute c = 6 in eqn 1</u></em>

14(6) + 5v = 119

84 + 5v = 119

5v = 119 - 84

5v = 35

v = 7

Thus cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7

8 0

3 years ago

A campus club held a bake sale as a fund raiser, selling coffee, muffins, and bacon and eggs sandwiches. The club members charge

OLEGan [10]

Answer:

The number of bacon and egg sandwiches sells are 2 .

Step-by-step explanation:

Let us assume that the number of coffee cups campus club sells be x .

Let us assume that the number of muffins cups campus club sells be y .

Let us assume that the number of bacon and eggs sandwiches campus club sells be z .

As given

Campus club sold a total of 55 items .

Thus the equation becomes

x + y + z = 55

Of the club members sold 5 more muffins than cups of coffee .

Thus

Number of muffins = 5 + Number of cups of coffee

y = 5 + x

Putting the value of y in the equation x + y + z = 55 .

x + 5 + x + z = 55

2x + z = 55- 5

2x + z = 50

As given

The club members charged $1 for a cup of coffee, 3$ for a muffin , and $4 for a bacon and egg sandwich and earns $119 .

Thus the equation becomes

x + 3y + 4z = 119

Putting the value of y in the above

x + 3 × (x + 5) + 4z = 119

x + 3x + 15 + 4z = 119

4x + 4z = 119 - 15

4x + 4z = 104

Simplify the above

x + z = 26

Thus the two equations are

2x + z = 50

x + z = 26

Multiply x + z = 26 subtracted from 2x + z = 50.

2x -x + z - z = 50 - 26

x = 24

Put the value of x in x + z = 26 .

24 + z =26

z = 26 - 24

z = 2

Therefore the number of bacon and egg sandwiches sells are 2 .

7 0

3 years ago