Answer : 110 degree
To find angle 1 , we apply outside angle theorem Lets name each point Measurement of arc EF=280 degrees
Measurement of arc GH = 60
Angle D = angle 1
Please refer to the theorem attached below
![angle D = \frac{arc(EF)-arc(GH)}{2}](https://tex.z-dn.net/?f=angle%20D%20%3D%20%5Cfrac%7Barc%28EF%29-arc%28GH%29%7D%7B2%7D)
Now we plug in the values
![angle 1 = \frac{280-60}{2}](https://tex.z-dn.net/?f=angle%201%20%3D%20%5Cfrac%7B280-60%7D%7B2%7D)
angle 1 = 110
Measurement of angle 1 = 110 degrees
I think you can use cosine rule if only the lines that form the <52 are equal.
Answer:
X = 5
Step-by-step explanation:
Here is what I am picturing (not to scale)
A ----------------B-----------C
We are given the information of AB (which equals 3x + 1), BC (which equals 4x - 5), and AC (which equals 8x - 9).
With reference to the line, AB + BC = AC
So,
3x + 1 + 4x - 5 = 8x - 9
7x - 4 = 8x - 9
5 = x
Tan = opposite / adjacent
tan 74 = 24/7
Answer:
the answer is the letter a) -sin x
Step-by-step explanation:
Simplify the expression.
sine of x to the second power minus one divided by cosine of negative x
(1−sin2(x))/(sin(x)−csc(x))
sin2x+cos2x=11−sin2x=cos2x
cos2(x)/(sin(x)−csc(x))csc(x)=1/sin(x)cos2(x)/(sin(x)− 1/sin(x))= cos2(x)/((sin2(x)− 1)/sin(x))sin2(x)− 1=-cos2(x)cos2(x)/(( -cos2(x))/sin(x))
=-sin(x)