1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Olenka [21]
3 years ago
6

Where would an imaginary line need to be drawn to reflect across an axis of symmetry so that a regular pentagon can carry onto i

tself?
Mathematics
2 answers:
oksano4ka [1.4K]3 years ago
3 0

The <em><u>correct answer</u></em> is:

A line of reflection would need to be drawn as a line that bisects a vertex angle of the pentagon.

Explanation:

A line that bisects a vertex angle of a pentagon will be a line of symmetry within the pentagon. The pentagon can be "folded" through this line into two equal halves.

This imaginary line represents the center of the pentagon. A reflection through this line will carry the pentagon onto itself. This is due to the definition of line symmetry:

"A set of points has line symmetry if and only if there is a line, l, such that the reflection through l of each point in the set is also a point in the set."

Additionally, for any regular polygon, the number of lines of symmetry equals the number of sides.

This means that this line can be through any vertex angle of the polygon.

Ber [7]3 years ago
3 0
It seems that you have missed the necessary options to answer this question, but anyway, here is the answer. An imaginary line would need to be drawn at any angle to the center of the side opposite the angle to <span>reflect across an axis of symmetry so that a regular pentagon can carry onto itself. Hope this answer helps.</span>
You might be interested in
Who would be incorrect?
telo118 [61]
Student B answered correctly
6 0
3 years ago
Read 2 more answers
Use the table of integrals, or a computer or calculator with symbolic integration capabilities, to find the indefinite integral.
nignag [31]

Answer:

-\frac{3}{11}\ln(\cot t + \csc t)+C

Step-by-step explanation:

We are given:  \int \frac{3}{x\sqrt{121-x^2}} dx

We will use integration by parts.

x = 11 \sin t\\dx = 11 \cos t \: dt

\int \frac{3}{x\sqrt{121-x^2}} dx=\int \frac{3* 11 \cos t \: dt}{11 \sin t\sqrt{121-121\sin^2 t}} =\int \frac{3* 11 \cos t \: dt}{11 \sin t*11\cos t}} =\\\\= \frac{3}{11} \int \csc t = -\frac{3}{11}\ln(\cot t + \csc t)+C

4 0
4 years ago
The weight og Darrin's phone is 3.405 ounces. What is 3.405 written in expanded form?
Nesterboy [21]
The correct answer is A. 3 is in the ones place(3×1) 4 is in the tenths place(4×1/10) 0 is 0, and 5 is in the thousands place (5x1/1000)
8 0
3 years ago
Subtract: (3a + 2) - (4a + 6).
allsm [11]

Answer:

-a-4

Step-by-step explanation:

remove the parenthesis (or however you spell it..)

3a+2-4a-6

combine like terms

3a-4a+2-6

solve

-a-4

3 0
3 years ago
Guys help me please please please
ICE Princess25 [194]

Answer:

\left[\begin{array}{ccc}1&\frac{3}{4}\\2&\frac{9}{16}\\3&\frac{27}{48}\\4&\frac{81}{144}\end{array}\right]

Step-by-step explanation:

f(s) = \frac{3}{4}  * f(s - 1)

It is basically substituting the numbers in the function.


For 1, it will be

f(1) = \frac{3}{4} * f(1 - 1)

f(1) = \frac{3}{4} * f(0)

f(1) = \frac{3}{4} * 1

f(1) = \frac{3}{4}


Same for the rest.

6 0
3 years ago
Other questions:
  • What is the place value of all these numbers 228,227
    15·1 answer
  • Solve using elimination
    10·1 answer
  • Find the simple interest Mark owes on a four-year student loan of $36,000 with an annual interest rate of 6%.
    9·1 answer
  • Does anyone know the answer?
    11·1 answer
  • Explain how to find 40*50 using mental math?
    10·2 answers
  • Write an equation of the line that passes through point (5,6) and has a slope of 2.
    11·1 answer
  • Find the measure of x and y
    7·1 answer
  • Plssssssss help solve
    15·2 answers
  • Hey guys I need help with this question
    7·1 answer
  • What is the unit rate for 150:6?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!