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Olenka [21]
3 years ago
6

Where would an imaginary line need to be drawn to reflect across an axis of symmetry so that a regular pentagon can carry onto i

tself?
Mathematics
2 answers:
oksano4ka [1.4K]3 years ago
3 0

The <em><u>correct answer</u></em> is:

A line of reflection would need to be drawn as a line that bisects a vertex angle of the pentagon.

Explanation:

A line that bisects a vertex angle of a pentagon will be a line of symmetry within the pentagon. The pentagon can be "folded" through this line into two equal halves.

This imaginary line represents the center of the pentagon. A reflection through this line will carry the pentagon onto itself. This is due to the definition of line symmetry:

"A set of points has line symmetry if and only if there is a line, l, such that the reflection through l of each point in the set is also a point in the set."

Additionally, for any regular polygon, the number of lines of symmetry equals the number of sides.

This means that this line can be through any vertex angle of the polygon.

Ber [7]3 years ago
3 0
It seems that you have missed the necessary options to answer this question, but anyway, here is the answer. An imaginary line would need to be drawn at any angle to the center of the side opposite the angle to <span>reflect across an axis of symmetry so that a regular pentagon can carry onto itself. Hope this answer helps.</span>
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Right in equation that shows the relationship between time and distance use your equation to find out how long it would take in
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This couldn't be answered!
4 0
3 years ago
If you draw a card with a value of three or less from a standard deck of cards, I will pay you $43. If not, you pay me $11. (Ace
valina [46]

If W is a random variable representing your winnings from playing the game, then it has support

W=\begin{cases}43&\text{if you draw something with value at most 3}\\-11&\text{otherwise}\end{cases}

There are 52 cards in the deck. Only the 1s, 2s, and 3s fulfill the first condition, so there are 12 ways in which you can win $43. So W has PMF

P(W=w)=\begin{cases}\frac{12}{52}=\frac3{13}&\text{for }w=43\\1-\frac{12}{52}=\frac{10}{13}&\text{for }w=-11\\0&\text{otherwise}\end{cases}

You can expect to win

E[W]=\displaystyle\sum_ww\,P(W=w)=\frac{43\cdot3}{13}-\frac{11\cdot10}{13}=\boxed{\frac{19}{13}}

or about $1.46 per game.

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3 years ago
Whats the average cost to put wood floors in a 12 ft x 16 ft room?
Bas_tet [7]
Area in ft sq. × cost per ft sq.
8 0
4 years ago
25 points
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Find the distance between the points (<br> -<br> 10,12) and (15,12).
Nitella [24]
The distance formula is:

d= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

We are given two points in the form (x,y), so plug in the values to the distance formula:

d= \sqrt{(-10-15)^2-(12-12)^2}

Next we can simplify. We know that 12-12 is 0, so we can drop it from the equation, as it will not affect our answer. Also, we know that -10-15 is -25:

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The square and square root cancel each other out leaving us with 25.

The answer is 25.


5 0
3 years ago
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