We make use of the equation: v^2=v0^2+2a Δd. We substitute v^2 equals to zero since the final state is halting the truck. Hence we get the equation -<span>v0^2/2a = Δd. F = m a from the second law of motion. Rearranging, a = F/m
</span>F = μ Fn where the force to stop the truck is the force perpendicular or normal force multiplied by the static coefficient of friction. We substitute, -v0^2/2<span>μ Fn/m</span> = Δd. This is equal to
The image of the object is 8cm to the left of the lens (D)
<h3>
</h3>
What is the image of an object?
The image of an object is said to be the location where light rays from that object intersect with a mirror by reflection.
It is calculated thus:
1÷v = 1÷f - 1÷u
<h3>How to calculate the image of an object</h3>
From the formula
1÷v = 1÷f - 1÷u
<h3>
Where </h3>
V = image distance fromthe object
U = object
f = focal length
Substitute the values
1÷v = 1÷8 - 1÷ 4
1÷v = - 1÷8
Make v the subject of formula
v = -8cm
Therefore, the image of the object is 8cm to the left of the lens (D)
Learn more on focal length here:
brainly.com/question/25779311
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The best explanation for the difference in time is: A. The difference in weight doesn't affect the time, but they are affected differently by air resistance.
<h3>What is weight?</h3>
Weight can be defined as the force acting on an object or a physical body due to the effect of gravity. Also, the weight of an object (body) is typically measured in Newton.
<h3>The factors that affect weight.</h3>
Some of the factors that affect the weight that is possessed by an object or a physical body include the following:
In conclusion, the weight possessed by the shoe and shirt has no effect on time but would be affected differently by air resistance.
Read more on weight here: brainly.com/question/13833323
Answer:
Electric Field a the centre
Explanation:
<u>Given:</u>
Total charge on the semicircle =Q
Radius of the semicircle=R
Let consider a elemental charge on the semicircle at an angle
with the horizontal. Since the The charge distribution is symmetrical about y axis so the there will symmetrical charge on other side. The horizontal component will cancel out each other and vertical component will get added so let dE be the electric Field due to elemental charge
Let
be the charge per unit length such that

Total Electric Field at the centre

integrating 0 to 


So the Electric field at the centre is calculated.