We can rearrange the mirror equation before plugging our values in.
1/p = 1/f - 1/q.
1/p = 1/10cm - 1/40cm
1/p = 4/40cm - 1/40cm = 3/40cm
40cm=3p <-- cross multiplication
13.33cm = p
Now that we have the value of p, we can plug it into the magnification equation.
M=-16/13.33=1.2
1.2=h'/8cm
9.6=h'
So the height of the image produced by the mirror is 9.6cm.
The solution is 22 2(n+3)-4&6
Answer:
40 meters. look for the dot above the 20 on the x-axis and follow it over to the left.
Explanation:
A surface wave is a wave that travels along the surface of a medium. The medium is the matter through which the wave travels. Ocean waves are the best-known examples of surface waves. They travel on the surface of the water between the ocean and the air. (According to ck12.org)
So your answer would be A!
Answer:
Temperature will be 305 K
Explanation:
We have given The asteroid has a surface area 
Power absorbed P = 3800 watt
Boltzmann constant 
According to Boltzmann rule power radiated is given by




So temperature will be 305 K