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3 years ago

6

How does your education contribute to comunity development

1 answer:

Angelina_Jolie [31]3 years ago

4 0

Because everybody in community needs to be smart & have some type of knowledge

You might be interested in

3. One atom of silicon can properly be combined in a compound with A. One atom of chlorine. B. Three atoms of hydrogen. C. Two a

Paraphin [41]

C :<em>2 atoms of Oxygen can probably join 1 Silicon Atom</em>

4 0

3 years ago

A charged capacitor is connected to an ideal inductor. At time t = 0, the charge on the capacitor is equal to 6.00 μC. At time t

Len [333]

Answer:

$4.71\times 10^{-3}A$

Explanation:

$Q_{max}$ = Maximum charge stored by capacitor = 6 μC = 6 x 10⁻⁶ C

$t$ = time taken for charge on the capacitor to become zero = 2 ms = 2 x 10⁻³ s

Time period is given as

$T = 4t$

$T = 4(2\times 10^{-3})$

$T = 8\times 10^{-3} s$

Angular frequency is given as

$w = \frac{2\pi }{T}$

$w = \frac{2(3.14) }{8\times 10^{-3}}$

$w$ =785 rad/s

Charge at any time is given as

$Q(t) = Q_{max}Coswt$

Taking derivative both side relative to "t"

$\frac{\mathrm{d}Q(t) }{\mathrm{d} t} = \frac{\mathrm{d}(Q_{max}Coswt) }{\mathrm{d} t}$

$i(t)= -Q_{max} w Sinwt$

Amplitude of the current is given as

$i_{max}= Q_{max} w$

$i_{max}= (6\times 10^{-6}) (785)$

$i_{max}= 4.71\times 10^{-3}A$

8 0

3 years ago

Four copper wires of equal length are connected in series. Their cross-sectional areas are 1.6 cm2 , 1.2 cm2 , 4.4 cm2 , and 7 c

EleoNora [17]

Answer:

63.8 V

Explanation:

We are given that

$A_1=1.6 cm^2=1.6\times 10^{-4} m^2$

$1 cm^2=10^{-4} m^2$

$A_2=1.2 cm^2=1.2\times 10^{-4} m^2$

$A_3=4.4 cm^2=4.4\times 10^{-4} m^2$

$A_4=7 cm^2=7\times 10^{-4} m^2$

Potential difference,V=140 V

We know that

$R=\frac{\rho l}{A}$

According to question

$l_1=l_2=l_3=l_4=l$

In series

$R=R_1+R_2+R_3+R_4$

$R=\rho l(\frac{1}{A_1}+\frac{1}{A_2}+\frac{1}{A_3}+\frac{1}{A_4})$

$R=\rho l(\frac{1}{1.6\times 10^{-4}}+\frac{1}{1.2\times 10^{-4}}+\frac{1}{4.4\times 10^{-4}}+\frac{1}{7\times 10^{-4}})$

$R=\rho l(18284.6)$

$I=\frac{V}{R}=\frac{140}{\rho l\times 18284.6}$

Potential across 1.2 square cm= $V_1=IR_1=\frac{140}{\rho l\times 18284.6}\times \rho l(\frac{1}{1.2\times 10^{-4}}=63.8 V$

Hence, the voltage across the 1.2 square cm wire=63.8 V

3 0

3 years ago

If you're on the orbiting International Space Station with a box of feathers and a box of sand, how could you tell which is whic

const2013 [10]

Answer:

Poke or kick the boxes. The sand box is the one that resists the most

Explanation:

The one that resists the most a change in motion (inertia) is the one with the greater mass—the one filled with sand. Since we cannot open the boxes or perform any weight measurement we can distinguish them by their inertia. Sand has greater mass and thus greater inertia

4 0

3 years ago

What kind of earthquake related technologies are engineers and scientists working on currently?

dangina [55]

Answer:

Technologies such as seismographs, creepmeters, and laser beams are used to detect seismic events.

Explanation:

3 0

2 years ago