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Bezzdna [24]
2 years ago
6

Your boss asks you compare two sound waves and determine which has the higher frequency. Wave A has a period of 4⁄100 second and

Wave B has a period of 1⁄7 second. What would you tell your boss?
A. Wave B has the higher frequency. Its frequency is 7 Hz.
B. Wave A has the higher frequency. Its frequency is 25 Hz.
C. Wave B has the higher frequency. Its frequency is 42 Hz.
D. Wave A has the higher frequency. Its frequency is 4 Hz.
Physics
2 answers:
s2008m [1.1K]2 years ago
8 0

<u>Answer</u>

B. Wave A has the higher frequency. Its frequency is 25 Hz.


<u>Explanation</u>

Frequency is the number of oscillation/revolutions in a unit time. On the other hand, period is the time taken to complete one oscillation/revolution.

From the definition above we can conclude that, frequency(f) is the reciprocal of period(T). That is;

f = 1/T and

T = 1/f


Wave A

f = 1/(4/100)

= 100/4

= 25 Hz

Wave B

f = 1/(1/7)

= 7/1

= 7 Hz

So, <em>wave A has the higher frequency. Its frequency is 25 Hz.</em>

a_sh-v [17]2 years ago
6 0

<u>Answer:</u> The correct answer is Option B.

<u>Explanation:</u>

Frequency is defined as the reciprocal of time period. It is measured in Hertz(Hz) or Sec^{-1}.

\nu=\frac{1}{\text{Time Period}}

For wave A:

Time period given is \frac{4}{100}seconds. So, frequency will be:

\nu_A=\frac{1}{4/100}=\frac{100}{4}=25Hz

For wave B:

Time period given is \frac{1}{7}seconds. So, frequency will be:

\nu_B=\frac{1}{1/7}=\frac{7}{1}=7Hz

From above, we can say that the frequency of wave A is more than the frequency of wave B.

Hence, the correct answer is Option B.

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Two astronauts of mass 100 kg are 2 m apart in outer space. What is the
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The force of gravity between the astronauts is 1.67\cdot 10^{-7}N

Explanation:

The magnitude of the gravitational force between two objects is given by:

F=G\frac{m_1 m_2}{r^2}

where :

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2} is the gravitational constant

m_1, m_2 are the masses of the two objects

r is the separation between them

In this problem, we have two astronauts, whose masses are:

m_1 = 100 kg\\m_2 = 100 kg

While the separation between the astronauts is

r = 2 m

Substituting into the equation, we can find the gravitational force between the two astronauts:

F=\frac{(6.67\cdot 10^{-11})(100)(100)}{2^2}=1.67\cdot 10^{-7}N

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What type of material is wrapped around an object could cause the object to lose the most heat
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A horizontal force of 750 N is needed to overcome the force of static friction between a level floor and a 250-kg crate. What is
Aleksandr [31]

Answer:

The acceleration of the crate is 1.8 m/s² so the answer is a.

Explanation:

The very first thing you must do when solving this problem is to draw a free body diagram. (The body diagram is attached to this answer)

So once we got the free body diagram, we can analyze it and build our sum of forces in the x and y directions. Notice that according to the diagram, there are 4 forces to this problem, Normal (N), Weight (W), kinetic friction (fk) and the 750N force.

As one may see in the free body diagram, two of the forces are vertical forces: N and W, so we can use them to build a sum of forces:

Starting with the sum of forces in the y-direction, we get:

ΣF_{y}=0

We set the sum equal to zero because there is no movement in the y-direction, so the system is in vertical equilibrium.

so the sum will be:

N-W=0

when solving for N we get that:

N=W

where W is found by multiplying the mass of the crate by the acceleration of gravity:

N=250kg*9.8m/s²

N=2450N

Once we found the normal force, we can use it to find the kinetic friction which is given by the following formula:

f_{k}=Nμ

where μ is the kinetic friction coefficient.

So we get that the kinetic friction is:

f_{k}=2450N*0.12

so

f_{k}=294

With this information we can go ahead and find the sum of horizontal forces:

ΣF_{x}=ma

In this case the sum is equal to mass times acceleration because the crate is moving horizontally due to the action of a force, so it will have an acceleration.

so the sum of forces look like this:

750N-f_{k}=ma

so

750N-294N=(250kg)a

when solving for a we get:

a=\frac{759N-294N}{250kg}\\ \\a=1.8m/s^{2}

so the crate's acceleration is 1.82m/s².

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