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goldfiish [28.3K]
3 years ago
15

Simplify √5(8+3√6) using radicals

Mathematics
1 answer:
hichkok12 [17]3 years ago
3 0
Your answer should be 34
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Tessellations that use only one type of regular polygon are called semi-regular tessellations. A. True B. False
Sauron [17]

The answer is B... False. Tansellations that use only one type of regular polygon are not called semi-regular tessellations

5 0
3 years ago
HELP!!!!!!!!!!!!!!!!!!
maxonik [38]

Answer:

Concept: Area

  • Area= (3.14)r^2
  • Hence 3.14 * 7^2
  • 3.14* 49 =153.86
  • Divide by 4 for the qualifications
  • 153.86/4= 38.47
7 0
3 years ago
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Can help my little bro
lisabon 2012 [21]

Answer:

$0.03

Step-by-step explanation:

chips: 7.84/16=0.49

pretzels: 12.48/24=0.52

0.52=0.49=0.03

7 0
3 years ago
2. A lunch stand makes s.75 profit on each chef's salad and $1.20 profit on each Caesar salad. On a typical weekday, it sells be
kow [346]

Let's let

<u>x = the number of chef salads, x>=0</u>

<u>y = the number of Caesar salads, y>=0</u>

The constrains are:

40 <= x <= 60

35 <= y <= 50

x + y <= 100

The objective function here is F(x, y) = 0.75x + 1.20y

The corner points are (40, 35),  (60, 35), (60, 40), (50, 50) and (40, 50).

F (40, 35) = 0.75*40 + 1.20*35 = $72

F (60, 35) = 0.70*60 + 1.20*35 = $84

F (60, 40) = 0.75*60 + 1.20*40 = $93

F (50, 50) = 0.75*50 + 1.20*50 = $97.50

F (40, 50) = 0.75*40 + 1.20*50 = $90

Thus, we conclude to maximize the profit 50 Chef and 50 Caesar salads should be prepared.

8 0
4 years ago
In quadrilateral $ABCD$, we have $AB=3,$ $BC=6,$ $CD=4,$ and $DA=4$.
vampirchik [111]
The triangle inequality applies.

In order for ACD to be a triangle, the length of AC must lie between CD-DA=0 and CD+DA=8.

In order for ABD to be a triangle, the length of AC must lie between BC-AB=3 and BC+AB=9.

The values common to both these restrictions are numbers between 3 and 8. Assuming we don't want the diagonal to be coincident with any sides, its integer length will be one of ...
{4, 5, 6, 7}
8 0
3 years ago
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