Use Coulomb law: F = k * q1*q2 / (r^2), where k = 9.00 * 10^9 N.m^2/C^2
F = 9.00 * 10^9 N.m^2/C^2 * 2.4*10^-8 C * 1.8*10^-6 C / [0.008m]^2 = 38.88 * 10^ -5 N
F = 39 * 10 -5N
Answer:
An object in a motion when it is continuously changing its position based on a reference point and observed by a person or a device.
Answer:
41.2 m.
Explanation:
It takes half the time that is (5.8/2) = 2.9 seconds, for the ball to reach its apex.
Given:
S = 83 m
t = 5.8 s
vf = 0 m/s
a = - g
= - 9.81 m/s^2
Equations of motion:
i. vf = vi + a * t
ii. h = vi * t + 1/2 (a * t²)
Using the i. equation of motion:
0 m/s = vi - (9.8 m/s²) (2.9 sec)
vi = 28.4 m/s.
Using the ii. equation of motion:
h = (28.4 * 2.9 ) - 1/2 (9.8 * (2.9)²)
= 82.4 - 41.2
= 41.2 m.
