Answer:
A car would need to be moving with a velocity of 28.86 m/s for its acceleration to be numerically equal to the acceleration due to gravity.
Explanation:
Radial acceleration for an object in circular motion is given by
α = v²/r
α = g = 9.8 m/s²
v = ?
r = 85 m
9.8 = v²/85
v² = 9.8 × 85 = 833
v = 28.86 m/s
Volume of the original block (V) of length (l), width (w) and height (h) is given by the following equation
hence volume of original block, V = (6)(4)(10) = 
Now say we cut this block in two equal parts, than the length of new block will be 
; where as its width and height will be same as of original block i.e. 4 cm and 10 cm respectively.
So, Volume of half-block is 
; or we can say that the volume of half-block is half that of orignal block.
Oxidation number for Xenon is XeOF2 and Argon is 0.
Answer:
a) V ≈ 125 m/s; b) Δt = 13.24 s; c) ΔS ≈ 1450 m
Explanation:
a) We have just to calculate the vector resultant.
V² = 106² + 66.2²
V² = 15618.44
V ≈ 125 m/s
b) The time of flight is equal to the time to reach the maximum height summed to the time to reach the land.
In vertical:
V = V₀ + a * t
V = 66.2 - g * t
0 = 66.2 - 9.8 * t
t ≈ 6.76 s
So: Δt = 13.24 s
c) In horizontal:
V = ΔS / Δt
106 = ΔS / 13.52 ⇒ ΔS = 106 * 13.52
ΔS = 106 * 13.52
ΔS = 1433,12
ΔS ≈ 1450 m
The answer is 138.75 kgm/s
Impulse (I) is the multiplication of force (F) and time interval (Δt): I = F · Δt
It is given:
m = 0.25
F = 18,500 N = 18,500 kgm/s²
Δt = 0.0075 s
I = ?
I = F · Δt = 18,500 5kgm/s² * 0.0075 s = 18,500 * 0.0075 kgm/s² * s = 138.75 kgm/s
