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Anon25 [30]
3 years ago
15

HELP PLEASE ASAPPPPPP

Physics
2 answers:
nignag [31]3 years ago
7 0

Answer:

A)a traveling surface wave

Explanation:

Nady [450]3 years ago
4 0

Answer:

It's A

Explanation:

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3 years ago
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A motorcyclist drives from a to b with the uniform speed of 30 km/h-1 and returns back with the speed of 20 km/h-1.find the aver
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30+20 =50
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3 years ago
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if you put something like apiece of cardboard between a magnet and a iron nail, the magnet still holds the nail. how?
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8 0
4 years ago
A student removes a 10.5 kg stereo amplifier from a shelf that is 1.82 m high. The amplifier is lowered at a constant speed to a
Nonamiya [84]

Answer:

(a) the work done by the student is 110.1 J

(b) The gravitational force that acts on the amplifier is 102.9 N

Explanation:

Given;

mass of the amplifier, m = 10.5 kg

initial position of the amplifier, x₀ = 1.82 m

final position of the amplifier, x₁ =0.75 m

The dispalcement of the amplifier Δx = x₁ - x₀ = 1.82 m - 0.75 m = 1.07 m

(b) The gravitational force that acts on the amplifier;

F = mg

F = 10.5 x 9.8

F = 102.9 N

(a) the work done by the student is calculated as;

W = FΔx

W = 102.9 x 1.07

W = 110.1 J

7 0
3 years ago
When point charges q = +8.4 uC and q2 = +5.6 uC are brought near each other, each experiences a repulsive force of magnitude 0.6
Bezzdna [24]

Answer:

Distance between the charges, r = 0.8 meters

Explanation:

Given that,

Charge 1, q_1=+8.4\ \mu C=+8.4\times 10^{-6}\ C

Charge 2, q_2=+5.6\ \mu C=+5.6\times 10^{-6}\ C

Repulsive force between charges, F = 0.66 N

Let r is the distance between charges. The formula for the electrostatic force is given by :

F=k\dfrac{q_1q_2}{r^2}

r=\sqrt{\dfrac{kq_1q_2}{F}}

r=\sqrt{\dfrac{9\times 10^9\times 8.4\times 10^{-6}\times 5.6\times 10^{-6}}{0.66}}

r = 0.8009 meters

or

r = 0.8 meters

So, the distance between the charges i 0.8 meters. Hence, this is the required solution.

4 0
3 years ago
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