A 139 kg physics professor has fallen into the Grand Canyon. Luckily, he managed to grab a branch and is now hanging 89 m below
the rim. A student (majoring in linguistics and physics) decides to perform a rescue/experiment using a nearby horse. After lowering a rope to her fallen hero and attaching the other end to the horse, the student measures how long it takes for the horse to pull the fallen physicist to the rim of the Grand Canyon. The acceleration of gravity is 9.8 m/s 2 . If the horse’s output power is truly 1 horsepower (746 W), and no energy is lost to friction, how long should the process take? Answer in units of s.
In order to lift the fat (306 lb) physics professor 89 meters up to the rim, he'll need more potential energy, equal to
(mass) x (gravity) x (height) = (139 x 9.8 x 89) = 121,236 joules .
If the faithful horse delivers 1 constant horsepower = 746 watts, AND if the cute-as-a-button student has instantly figured out a way to keep the rope sliding around the edge without any friction, then the soonest Prof. Tubby can arrive at the rim is
Nowhere in this tense drama has the student needed her linguistics skill yet, but I'll bet it comes in handy as she attempts gamely to comprehend all of the various pleadings, prayers, and expletives uttered by her heavy hero from the time he falls over the rim until he's again lifted to it.
<span>Like charges repel and opposite charges attract. The further away two charged objects are the weaker the electrical force between them. The closer two charged objects are the stronger the electrical force between them. Hope this helps :)</span>
The electric force between two charge objects is calculated through the Coulomb's law. F = kq₁q₂/d² The value of k is 9.0 x 10^9 Nm²/C² and the charge of proton is 1.602 x10^-19 C. Substituting the known values from the given, 2.30x10^-26 = (9.0 x 10^9 Nm²/C²)(1.602 x10^-19C)²/d² The value of d is equal to 0.10 m.
