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klio [65]
3 years ago
12

The original price of a bicycle was marked down $20 to a sale price of $85. What was the original price ⁉️

Mathematics
1 answer:
vovikov84 [41]3 years ago
4 0
The price was marked down. If the price was reduced, we have to sum with the other value to find the original price:

85 + 20 = \boxed {105}

The original price was $105.
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Fill in the missing value to make the equations true.
Furkat [3]

Answer:

a) 7/4 b) 5 c) 2

Step-by-step explanation:

Logrithmic Rule for a and b

Let a, M, N be positive real numbers.

a)  

logaM - logaN = loga(M/N)

log9(7) - log9(4) = log9 (7/4)

b)

logaM + logaN = logaMN

log2 (x) + log2(9) = log2(45)

x9=45

(x9)/9 = 45/9

x = 5

c)

Change of base formula.

logb​(x)=logd​(b)/logd​(x)​

x log6(5) = log6(25) divide each term by log6(5)

x log6(5) / log6(5) = log6(25) / log6(5)   Cancel common factor log6(5)

x = log6(25) / log6(5)

x = log6(5^2) / log6(5)

Expand log6(5^2) by moving 2 outside the logarithm.

x = 2log6(5) / log6(5) cancel the like term log6(5)

x = 2

7 0
3 years ago
Helppppp.. picture attached
tatyana61 [14]
n^2+n\\\\check:\\\\a_1=1^2+1=2\\a_2=2^2+2=6\\a_3=3^2+3=12\\a_4=4^2+4=20
6 0
3 years ago
Order these numbers from least to greatest: -3.8, 3<br> 3.-4, 0.
NeTakaya
The answer would be,
0, -4, -3.8, 3.3
8 0
3 years ago
A swim pass cost $30 dollars for the first month. Each month after that , the cost is 20$ per month. Riley wants to swim for 12
Zolol [24]

The answer is $250 for the 12 months.

7 0
3 years ago
A person gets on a Ferris wheel at the starting point. The starting point is 15 feet off the ground. The Ferris wheel has a radi
lisov135 [29]
<h2>Answer:</h2>

\boxed{\frac{25}{2}(\sqrt{6}+\sqrt{2})+65}

<h2>Explanation:</h2>

<em>The height of the rider from the ground after the Ferris wheel</em> equals <em>the starting point is 15 feet off the ground </em><em>plus </em><em>the radius of the Ferris wheel </em><em>plus </em><em>the opposite side of the triangle ΔABC </em>(See figure below).<em> </em>Hence our goal is to find this side. We have the angle 11\pi /2=165^{\circ}, therefore the angle ∠BAC = 165° - 90° = 75°. So this side can be found using trigonometry:

\overline{BC}=\overline{AB}sin(75^{\circ})=50sin(75^{\circ})=\frac{25}{2}(\sqrt{6}+\sqrt{2})

Finally, the height is:

H=\frac{25}{2}(\sqrt{6}+\sqrt{2})+15+50 \\ \\ \boxed{H=\frac{25}{2}(\sqrt{6}+\sqrt{2})+65}

6 0
3 years ago
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