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levacccp [35]
3 years ago
13

The gauge pressure in your car tires is 2.50×105N/m2 at a temperature of 35.0ºC when you drive it onto a ferry boat to Alaska. W

hat is their gauge pressure later, when their temperature has dropped to –40.0ºC
Physics
1 answer:
vlada-n [284]3 years ago
8 0

Answer:

1.645 x 10^5 Pa

Explanation:

Let Po be the atmospheric pressure. Po = 1.01 x 10^5 Pa

P1 = 2.5 x 10^5 + Po = 2.5 x 10^5 + 1.01 x 10^5 = 3.51 x 10^5 Pa

T1 = 35 degree C = 35 + 273 = 308 k

T2 = - 40 degree C = - 40 + 273 = 233 k

Let the gauge pressure be P

So, P2 = P + Po

use

P1 / T1 = P2 / T2

3.51 x 10^5 / 308 = P2 / 233

P2 = 2.655 x 10^5

P + Po = 2.655 x 10^5

P = 2.655 x 10^5 - 1.01 x 10^5 = 1.645 x 10^5 Pa

Thus, the gauge pressure is 1.645 x 10^5 Pa.

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Answer:

Explanation:

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H = 27²/2(9.81)

H = 729/19.62

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true

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3 years ago
Read 2 more answers
A sled plus passenger with total mass m = 52.3 kg is pulled a distance d = 21.8 m across a horizontal, snow-packed surface for w
Vikki [24]

Answer:

Explanation:

Since the sled plus passenger moves with constant velocity , force applied will be equal to frictional force. Let the force applied be F

a ) Frictional force = μ R = F cosφ

R = mg - F sinφ

μ(mg - F sinφ)  = F cosφ

μmg = F (μsinφ+cosφ)

F = μmg / (μsinφ+cosφ)

Work done

= F cosφ x d

= μmg x cosφ x d / (μsinφ+cosφ)

b )Work done

= 0.13 x 52.3 x 9.8 cos36.7 x 21.8 / ( 0.13 sin36.7 +cos36.7)

= 1164.61 / .87946

1324.23 J

c ) work done on the sled by friction

= - (work done by force)

= - μmg x cosφ x d / (μsinφ+cosφ)

d ) work done on the sled by friction

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4 years ago
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kodGreya [7K]

Answer:

The interpretation of the subject in question is characterized in the discussion section below.

Explanation:

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