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2 years ago

A baseball is hit into the air with a velocity of 27 m/s. How high does it go?

Physics

1 answer:

Marizza181 [45]2 years ago

8 0

Answer:

Explanation:

If a baseball is hit into the air with a velocity of 27 m/s, we want to determine the maximum height of the ball. Using the projecile formula;

Max height H = u²/2g

u is the initial velocity of the body = 27m/s

g is the acceleration due to gravity = 9.81m/s²

H = 27²/2(9.81)

H = 729/19.62

H = 37.16m

Hence the ball went 37.16m high

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dangina [55]

Answer:

4.44 rpm

Explanation:

$\omega$ = Angular speed

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R = Radius of arm = 6 m

The acceleration due to gravity is given by

$g=\frac{GM}{r^2}\\\Rightarrow g=\frac{6.67\times 10^{-11}\times 4.8\times 10^{22}}{\left(\frac{3138000}{2}\right)^2}\\\Rightarrow g=1.3\ m/s^2$

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Converting to rpm

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2 years ago

Which material is a conductor? A. chalk B. lead C. leather D. paper E. rubber

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B. Lead is a conductor....

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A rocket is fired at 100 m/s at an angle of 37, what was its speed at the top of its path?

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