3 years ago

A baseball is hit into the air with a velocity of 27 m/s. How high does it go?

Physics

1 answer:

Marizza181 [45]3 years ago

8 0

Answer:

Explanation:

If a baseball is hit into the air with a velocity of 27 m/s, we want to determine the maximum height of the ball. Using the projecile formula;

Max height H = u²/2g

u is the initial velocity of the body = 27m/s

g is the acceleration due to gravity = 9.81m/s²

H = 27²/2(9.81)

H = 729/19.62

H = 37.16m

Hence the ball went 37.16m high

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3 years ago

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Explanation:

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Upper Temprature $\left ( T_H\right )=240^{\circ}\approx 513$

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rounding off to two significant figures

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3 years ago

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Let the slope of the best fit line be represented by ' $m_{best}$ '

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$\Delta m = \frac{m_{best}-m_{worst}}{2}$ (1)

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