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umka21 [38]
3 years ago
8

** PLEASE PLEASE HELP A student uses the right-hand rule as shown.

Physics
2 answers:
guapka [62]3 years ago
7 0

As per right hand thumb rule if we put our thumb of right hand along the current in the wire then curl of fingers will show the direction of magnetic field.

So here as we can see the fingers in the above case is curled such that in front position its showing towards right.

So the direction of magnetic field near the student in front position must be towards Right.

elena-14-01-66 [18.8K]3 years ago
5 0

What is the direction of the magnetic field in front of the wire closest to the student?


B) Right

                                                                                                                                           

                                                                                                                                                 

                                                                                                                                               

                                                                                                                                                                                                                                                                                                       

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A remote controlled toy car starts from rest and begins to accelerate in a straight line. The figure below represents "snapshots
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(a). The car's average velocity between t = 1.0s to t = 1.5s will be - 1\;m/s

(b). The car's acceleration at t = 1.5s will be - 0.4\;m/s^{2}

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We have a a remote controlled toy car that starts from rest and begins to accelerate in a straight line.

We have to determine -

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<h3>What is Acceleration?</h3>

The rate of change of velocity with respect to time is called Acceleration. Mathematically -

$a=\frac{dv}{dt}

According to the question, we have the following data for the Car -

t = 0s → x = 0m

t = 0.5s → x = 0.1m

t = 1.0s → x = 0.4m

t = 1.5s → x = 0.9m

t = 2.0s → x = 1.6m

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The car's average velocity between t = 1.0s to t = 1.5s will be -

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PART - B

Velocity at t = 1.5 s will be -

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The car's acceleration at t = 1.5s will be -

$a(1.5) = \frac{v}{t} = \frac{0.6}{1.5} = 0.4\;m/s^{2}

PART - C

Since, the acceleration of the car is positive, this means that the car is accelerating in the forward direction. Hence, its speed is increasing with time.

[ The following data was missing in your answer. The complete question would include this data also -

t = 0s → x = 0m

t = 0.5s → x = 0.1m

t = 1.0s → x = 0.4m

t = 1.5s → x = 0.9m

t = 2.0s → x = 1.6m ]

To solve more questions on Kinematics, visit the link below-

brainly.com/question/17272824

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