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ladessa [460]
4 years ago
14

1. A uniform magnetic field is directed vertically upwards. In which direction in this field should an alpha particle be project

ed so that it is deflected south ward? Name and state the rule you have used to find the direction in this case.
Physics
1 answer:
max2010maxim [7]4 years ago
3 0

Answer:

1. Fleming's left hand rule

2. It must be projected towards the east

Explanation:

Fleming's left-hand rule states that; When a current-carrying conductor is placed in an external magnetic field, the conductor experiences a force perpendicular to both the field and to the direction of the current flow. This rule was first put forward by John Ambrose Fleming in the later part of the nineteenth century.

Hence if the thumb, fore finger and middle finger of the lefthand are held mutually at right angles to each other; the thumb shows the direction of motion, the fore finger shows the direction of the field while the middle finger shows the direction of the current.

Hence, if the alpha particle is projected eastwards(at right angles) to the uniform magnetic field, it will be deflected southwards in the magnetic field.

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3 years ago
A space station sounds an alert signal at time intervals of 1.00 h . Spaceships A and B pass the station, both moving at 0.400c0
balandron [24]

Answer:

a)  Time interval between signals according to an observer on spaceship A  = 1.09h

b)  Time interval between signals according to an observer on spaceship B = 1.09h

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Explanation:

a) Time interval between signals according to an observer on spaceship A

Initial time intervals for the alert signal, Δt₀ = 1.00h

The speed of spaceship A, v = 0.400c

The formula for the time interval is given by

Δt = ∆t₀ /√(1-(v/c)² )

Δt = 1 / √(1-(0.4c/c)² )

Δt = 1 / √(1-(0.4)²

Δt = 1.09 h

b) The intervals between signals according to an observer on spaceship A and B are equal because both spaceships are moving at the same speed.

Therefore, the time interval between signals according to an observer on B is Δt = 1.09 h

c) The speed of A relative to the station to measure a time interval of 2.00h

Δt = ∆t₀ /√(1-(v/c)² )

2 = 1 /√(1-(v/c)² )

√(1-(v/c)² ) = 0.5

1-(v/c)² = 0.25

0.75 = (v/c)²

v/c = 0.866

v = 0.866c

v = 0.866 * 3 * 10⁸

v = 2.6 * 10⁸ m/s

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3 years ago
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maxonik [38]
<em>The answer you are looking for is: </em>
<em><u>A.) Transfer energy by vibrating particles of matter </u></em>
<em>Hope that helps/!!! </em>
<em>Have a wonderful day!!! </em>
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