The process by which nitrogen gas is converted to a usable form called nitrogen what

A 65.0-gram sample of some unknown metal at 100.0° C is added to 177.1 grams of water at 24.5° C. The temperature of the water r

jeka94

B.) 0.900 J/ (°C × g).

7 0

3 years ago

Find a substance that has a specific heat that is higher than liquid water and explain what it means.

svlad2 [7]

Liquid ammonia
liquid lithium 

What it means? It means that, for the same amount of energy input, one grams of either of the above two will go up a lesser number of degrees Celsius than water will.

7 0

3 years ago

Read 2 more answers

Match the chemical Equation with his correct type

Alex

Answer:

The answer to your question is given below

Explanation:

1. C. 2NaCl + I2 —> 2NaI + Cl2 => C. Single displacement.

From the above equation, we can see that I2 replaces Cl in NaCl to produce NaI. This is simply called a single displacement reaction.

2. E. 2C4H10 + 13O2 —> 8CO2 + 10H2O => E. Combustion.

The above equation shows the burning of Hydrocarbon in the presence of O2. This is simply called Combustion as CO2 and H2O is produced.

3. D 2H2O —> 2H2 + O2 => D. Decomposition.

From the above equation, we can see that a single compound H2O produces two elements H2 and O2. This is simply called a decomposition reaction.

4. A. ZnS + 2HCl —> ZnCl2 + H2S => A. Double Decomposition.

From the above equation, we can see that Cl replaces S in ZnS to produce ZnCl2 and S replaces Cl in HCl to produce H2S. This is simply called double displacement reaction.

5. B. H2 + Br2 —> 2HBr => B. Synthesis.

From the above equation, we can see that two element H2 and Br2 combine to produce a single compound HBr. This is simply called a synthesis reaction.

7 0

3 years ago

Which has greater internal energy, 1 kg of water or 1 g of water, at the same temperature?

Natali5045456 [20]

1kg of water has greater internal energy compared to 1g of water because 1kg of water has more mass.

4 0

3 years ago

N2+3H2 → 2NH3

s2008m [1.1K]

Explanation:

N2 (g) + H2 (g) gives out NH3 (g)

Now balance it. You have two reactants with compositions involving a single element, which makes it very easy to keep track of how much is on each side. I would balance the nitrogens, and then the hydrogens.

Now balance it. You have two reactants with compositions involving a single element, which makes it very easy to keep track of how much is on each side. I would balance the nitrogens, and then the hydrogens.(If you balance the hydrogen reactant with a whole number first, I can guarantee you that you will have to give NH3 a new stoichiometric coefficient.)

N2 (g) + 3H2 (g) gives out 2NH3 (g)

The stoichiometric coefficients tell you that if we can somehow treat every component in the reaction as the same (like on a per-mol basis, hinthint), then one "[molar] equivalent" of nitrogen yields two [molar] equivalents of ammonia.

Luckily, one mol of anything is equal in quantity to one mol of anything else because the comparison is made in the units of mols.

So what do we do? Convert to

mols (remember the hint?).

28g N2 × 1 mol N2/ 2 × 14.007) g N2

= 0.9995 mol N2

At this point you don't even need to calculate the number of mols of H2 . Why? Because H2 is about 2 g/mol, which means we have over 10 mols of H2. We have 1 mol N2, and we need three times as many mols of H2 as we have

N2.

After doing the actual calculation you should realize that we have about 4 times as much H2 as we need. Therefore the limiting reagent is clearly N2.

Thus, we should yield 2×0.9995=1.9990 mols of NH3 (refer back to the reaction). So this is the second and last calculation we need to do:

1.9990 mol NH3 × 17.0307 g NH3/ 1 mol NH3

= 34.0444 g NH3

Hope it helpz~

4 0

2 years ago