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alekssr [168]
3 years ago
10

How would you properly measure the mass of a liquid

Chemistry
1 answer:
MArishka [77]3 years ago
4 0
You can consider the density of the water. Thus, in order to properly measure the mass of a liquid, we can first get the volume and density of the liquid material or substance. We can firstly utilize the formula to get the mass from deriving the set formula of density to mass: Since density is mass over the volume, <span><span>
1.  </span>D=m/v</span> <span><span>
2.  </span>We can transmute the formula to m = dv</span>
<span><span>3.  </span>Mass is density times the volume</span>



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an aqeous solution of oxalic acid h2c2o4 was prepared by dissolving a 0.5842g of solute in enough water to make a 100 ml solutio
vampirchik [111]

The question is incomplete, here is the complete question:

An aqeous solution of oxalic acid was prepared by dissolving a 0.5842 g of solute in enough water to make a 100 ml solution a 10 ml aliquot of this solution was then transferred to a volumetric flask and diluted to a final volume of 250 ml. How many grams of oxalic acid are in 100. mL of the final solution?

<u>Answer:</u> The mass of oxalic acid in final solution is 0.0234 grams

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}     ......(1)

Given mass of oxalic acid = 0.5842 g

Molar mass of oxalic acid = 90 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

\text{Molarity of oxalic acid solution}=\frac{0.5842\times 1000}{90\times 100}\\\\\text{Molarity of oxalic acid solution}=0.0649M

To calculate the molarity of the diluted solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated oxalic acid solution

M_2\text{ and }V_2 are the molarity and volume of diluted oxalic acid solution

We are given:

M_1=0.0649M\\V_1=10mL\\M_2=?M\\V_2=250.0mL

Putting values in above equation, we get:

0.0649\times 10=M_2\times 250.0\\\\M_2=\frac{0.0649\times 10}{250}=0.0026M

Now, calculating the mass of glucose by using equation 1, we get:

Molarity of oxalic acid solution = 0.0026 M

Molar mass of oxalic acid = 90 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

0.0026=\frac{\text{Mass of oxalic acid solution}\times 1000}{90\times 100}\\\\\text{Mass of oxalic acid solution}=\frac{0.0026\times 90\times 100}{1000}=0.0234g

Hence, the mass of oxalic acid in final solution is 0.0234 grams

6 0
4 years ago
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