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alekssr [168]
3 years ago
10

How would you properly measure the mass of a liquid

Chemistry
1 answer:
MArishka [77]3 years ago
4 0
You can consider the density of the water. Thus, in order to properly measure the mass of a liquid, we can first get the volume and density of the liquid material or substance. We can firstly utilize the formula to get the mass from deriving the set formula of density to mass: Since density is mass over the volume, <span><span>
1.  </span>D=m/v</span> <span><span>
2.  </span>We can transmute the formula to m = dv</span>
<span><span>3.  </span>Mass is density times the volume</span>



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A 825 g iron block is heated to 352 degrees C and is placed in an insulated container (of negligible heat capacity) containing 4
Stella [2.4K]

Answer : The final equilibrium temperature of the water and iron is, 537.12 K

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of iron =  560 J/(kg.K)

c_1 = specific heat of water = 4186 J/(kg.K)

m_1 = mass of iron = 825 g

m_2 = mass of water = 40 g

T_f = final temperature of water and iron = ?

T_1 = initial temperature of iron = 352^oC=273+352=625K

T_2 = initial temperature of water = 20^oC=273+20=293K

Now put all the given values in the above formula, we get:

(825\times 10^{-3}kg)\times 560J/(kg.K)\times (T_f-625K)=-(40\times 10^{-3}kg)\times 4186J/(kg.K)\times (T_f-293K)

T_f=537.12K

Therefore, the final equilibrium temperature of the water and iron is, 537.12 K

8 0
3 years ago
Help help help.
Whitepunk [10]
I think B
Hope this helps!
4 0
3 years ago
g 1.000 atm of oxygen gas, placed in a container having a pinhole opening in its side, leaks from the container 2.14 times faste
Ivan

The question is incomplete, the complete question is;

1.000 atm of Oxygen gas, placed in a container having apinhole opening in its side. leaks from the container 2.14 timesfaster thatn 1.000 atm of an unknown gas placed in this sameapparatus. Which of the following species could be theunknown gas?

A. CL2

B. SF6

C. Kr

D. UF6

E. Xe

Answer:

SF6

Explanation:

From Graham's law;

Let the rate of diffusion of oxygen be R1

Let the rate of diffusion of unknown base be R2

Let the molar mass of oxygen by M1

Let the molar mass of unknown gas be M2

Hence;

R1/R2 = √M2/M1

So;

2.14/1 = √M2/32

(2.14/1)^2 = M/32

M= (2.14/1)^2 × 32

M= 146.6

This is the molar mass of SF6 hence the answer above.

7 0
3 years ago
Is my answer correct?
natta225 [31]

Yes the ANSWER is Correct-

On first half life the mass will be 10 gram

On second half life the mass will be 5 gram

On third half life the mass will be 2.5 gram

3 0
3 years ago
When light energy excites electrons in photosystem II, where do the electrons to replace them come from?
Artyom0805 [142]
Oh we have just done this in biology recently... photolysis occurs where it splits apart water molecules to make electrons and hydrogen ions (the H+ is used to reduce NaDP later on) and also O₂ is made as a by product

basically this is the equation 2H₂O⇒4e⁻ + 4H⁺  where the electrons replace the lost ones in chlorophyll

hope this helped :)
3 0
3 years ago
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