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Zina [86]
3 years ago
13

A space probe on the surface of mars sends a radio signal back to earth,a distance of 7.19 ×10⁷ km. Radio travel at the speed of

light (3.00 ×10⁸ m/s). How many seconds does it take for the signal to reach the earth?
Chemistry
1 answer:
lys-0071 [83]3 years ago
6 0

Answer:

240 seconds

Explanation:

Data Given:

Distance Radio travel to earth = 7.19 ×10⁷ km

Speed of this radio signal = 3.00 ×10⁸ m/s

Solution:

First convert Km to m

1 km = 1000 m

7.19 ×10⁷ km = 7.19 ×10⁷ x 1000 = 7.19 × 10¹⁰m

Formula used to calculate time

            Speed (S) = distance (d) / time (t)

rearrange above equation for time

            time (t) = distance (d) / Speed (S) . . . . . . . . .(1)

Put values in equation 1

            time (t) = 7.19 × 10¹⁰/ 3.00 ×10⁸ m/s

            time (t) = 240 s

So 240 seconds it take for the signal to reach the earth

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<h3>Answer:</h3>

0.424 J/g °C

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
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Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Chemistry</u>

<u>Thermochemistry</u>

Specific Heat Formula: q = mcΔT

  • q is heat (in Joules)
  • m is mass (in grams)
  • c is specific heat (in J/g °C)
  • ΔT is change in temperature
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] m = 38.8 g

[Given] q = 181 J

[Given] ΔT = 36.0 °C - 25.0 °C = 11.0 °C

[Solve] c

<u>Step 2: Solve for Specific Heat</u>

  1. Substitute in variables [Specific Heat Formula]:                                             181 J = (38.8 g)c(11.0 °C)
  2. Multiply:                                                                                                             181 J = (426.8 g °C)c
  3. [Division Property of Equality] Isolate <em>c</em>:                                                         0.424086 J/g °C = c
  4. Rewrite:                                                                                                             c = 0.424086 J/g °C

<u>Step 3: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.424086 J/g °C ≈ 0.424 J/g °C

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