Answer:
C: 61.0%, H: 15.3%, N: 23.7%
Explanation:
We can calculate the percent by mass of each element using the following expression.
%Element = (mass of the element/mass of the compound) × 100%
Carbon
%C = (7.34 g/12.04 g) × 100% = 61.0%
Hydrogen
%H = (1.85 g/12.04 g) × 100% = 15.3%
Nitrogen
%N = (2.85 g/12.04 g) × 100% = 23.7%
The percent composition of this compound is C: 61.0%, H: 15.3%, N: 23.7%.
D. Communication of results
solution given:
log k=4-
so,
On comparison
∆S°/R = 4
∆ S° = 4R
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A (3,5), B (1,7) ,C(-1,-3),D(1,-5)
M[1,1]= [Diagonals bisect each other]
C(-1,-3)
D(1,-5)
hence,
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