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2 years ago

Describe the three states of matter in terms of shape and volume

1 answer:

7 0

Shape
A gas is shapeless all other things being equal. It will, if put in a container, occupy every part of the container.

A liquid could also be thought of shapeless. If put in a container, it need not occupy the entire container. It will occupy as much as its calculated volume will permit it to occupy.

A solid will only occupy its original shape.

Volume
A gas will occupy whatever container it is put in within limits. You cannot put a 72 mols of gas in a mm^3 container without some amazing ability to apply a lot of pressure.

A liquid will occupy a volume determined by its density and mass. In general liquids cannot be compressed.

Whatever volume a solid has to start with, it will retain that volume all other things being equal.

This is actually very hard to describe.

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if an iron nail is placed in a glass of water the nail will sink. Is the density of iron smaller than or larger than the density

Gala2k [10]

It has more density when it sinks because the water pushes away thats why people float they are less dense

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2 years ago

A car experiences an average acceleration of 5.00 km/hr/s for 3.50 sec. What is the change in velocity of the car?

Mice21 [21]

17.5 km/hr is the answer

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3 years ago

Read 2 more answers

Write the difference between the reaction of Calcium and Aluminium with water.

guapka [62]

Answer:

Both gives hydroxides, but

Calcium reacts with water to give calcium hydroxide Ca(OH)2. this product is slightly soluble in water.

Aluminium is less reactive than Ca, so it reacts with only steam, to give aluminium hydroxide Al(OH)3. This product is insoluble in water.

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3 years ago

Which of the following is NOT a limiting factor for the number of possible compounds?

babymother [125]

Answer:

all elements have a different atomic number

Explanation:

Atomic number of element does not affect their reactions with others

6 0

3 years ago

A buffer contains 0.19 mol of propionic acid (C2H5COOH) and 0.26 mol of sodium propionate (C2H5COONa) in 1.20 L. You may want to

Snezhnost [94]

Explanation:

It is known that $pK_{a}$ of propionic acid = 4.87

And, initial concentration of propionic acid = $\frac{0.19}{1.20}$

= 0.158 M

Concentration of sodium propionate = \frac{0.26}{1.20}[/tex]

= 0.216 M

Now, in the given situation only propionic acid and sodium propionate are present .

Hence, pH = $pK_{a} + log(\frac{[salt]}{[acid]})$

= $4.87 + log \frac{0.216}{0.158}$

= 4.87 + log (1.36)

= 5.00

Therefore, when 0.02 mol NaOH is added then,

Moles of propionic acid = 0.19 - 0.02

= 0.17 mol

Hence, concentration of propionic acid = $\frac{0.17}{1.20 L}$

= 0.14 M

and, moles of sodium propionic acid = (0.26 + 0.02) mol

= 0.28 mol

Hence, concentration of sodium propionic acid will be calculated as follows.

$\frac{0.28 mol}{1.20 L}$

= 0.23 M

Therefore, calculate the pH upon addition of 0.02 mol of NaOH as follows.

pH = $pK_{a} + log(\frac{[salt]}{[acid]})$

= $4.87 + log \frac{0.23}{0.14}$

= 4.87 + log (1.64)

= 5.08

Hence, the pH of the buffer after the addition of 0.02 mol of NaOH is 5.08.

Therefore, when 0.02 mol HI is added then,

Moles of propionic acid = 0.19 + 0.02

= 0.21 mol

Hence, concentration of propionic acid = $\frac{0.21}{1.20 L}$

= 0.175 M

and, moles of sodium propionic acid = (0.26 - 0.02) mol

= 0.24 mol

Hence, concentration of sodium propionic acid will be calculated as follows.

$\frac{0.24 mol}{1.20 L}$

= 0.2 M

Therefore, calculate pH upon addition of 0.02 mol of HI as follows.

pH = $pK_{a} + log(\frac{[salt]}{[acid]})$

= $4.87 + log \frac{0.2}{0.175}$

= 4.87 + log (0.114)

= 4.98

Hence, the pH of the buffer after the addition of 0.02 mol of HI is 4.98.

7 0

3 years ago