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Arada [10]
3 years ago
15

Please help thank you!​

Mathematics
1 answer:
Setler79 [48]3 years ago
7 0

Answer:

(d) WEAK NEGATIVE ASSOCIATION.

Step-by-step explanation:

Pearson correlation (r) is defined as a factor which measures the linear dependence between two variables (x and y). It's also known as a parametric correlation.

Here, r = -0.19

Now, as r is NEGATIVE.

⇒ As the value of x increases , value of y decreases.

⇒There is a  NEGATIVE ASSOCIATION.

Now as the value of r is between 0 and ( -1). So the factor of variation is very small.

Hence, it is WEAK NEGATIVE ASSOCIATION.

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Answer:

D. -3

Step-by-step explanation:

3 0
3 years ago
One model for the spread of a virusis that the rate of spread is proportional to the product of the fraction of the population P
Darya [45]

Answer:

The differential equation for the model is

\frac{dP}{dt}=kP(1-P)

The model for P is

P(t)=\frac{1}{1-0.99e^{t/447}}

At half day of the 4th day (t=4.488), the population infected reaches 90,000.

Step-by-step explanation:

We can write the rate of spread of the virus as:

\frac{dP}{dt}=kP(1-P)

We know that P(0)=100 and P(3)=100+200=300.

We have to calculate t so that P(t)=0.9*100,000=90,000.

Solving the diferential equation

\frac{dP}{dt}=kP(1-P)\\\\ \int \frac{dP}{P-P^2} =k\int dt\\\\-ln(1-\frac{1}{P})+C_1=kt\\\\1-\frac{1}{P}=Ce^{-kt}\\\\\frac{1}{P}=1-Ce^{-kt}\\\\P=\frac{1}{1-Ce^{-kt}}

P(0)=  \frac{1}{1-Ce^{-kt}}=\frac{1}{1-C}=100\\\\1-C=0.01\\\\C=0.99\\\\\\P(3)=  \frac{1}{1-0.99e^{-3k}}=300\\\\1-0.99e^{-3k}=\frac{1}{300}=0.99e^{-3k}=1-1/300=0.997\\\\e^{-3k}=0.997/0.99=1.007\\\\-3k=ln(1.007)=0.007\\\\k=-0.007/3=-0.00224=-1/447

Then the model for the population infected at time t is:

P(t)=\frac{1}{1-0.99e^{t/447}}

Now, we can calculate t for P(t)=90,000

P(t)=\frac{1}{1-0.99e^{t/447}}=90,000\\\\1-0.99e^{t/447}=1/90,000 \\\\0.99e^{t/447}=1-1/90,000=0.999988889\\\\e^{t/447}=1.010089787\\\\ t/447=ln(1.010089787)\\\\t=447ln(1.010089787)=447*0.010039225=4.487533

At half day of the 4th day (t=4.488), the population infected reaches 90,000.

8 0
3 years ago
The senior class at High School A and High School B is planning seperate trips to the local museum. The senior class at High Sch
tatiyna

Answer:

Number of students van can carry = 11

Number of students bus can carry = 41

Step-by-step explanation:

Given the following :

HIGH SCHOOL A:

Number of students = 184

Number of vans(v) = 13

Number of buses(b) = 1

Mathematically,

13v + 1b = 184 - - - - (1)

HIGH SCHOOL B:

Number of students = 520

Number of vans(v) = 10

Number of buses(b) = 10

Mathematically,

10v + 10b = 520 - - - - (2)

Multiply (1) by 10 and (2) by 1

130v + 10b = 1840 - - - (3)

10v + 10b = 520 - - - (4)

Subtract (4) from (3)

120v = 1320

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Substitute v = 11 into (1)

13(11) + 1b = 184

143 + b = 184

b = 184 - 143

b = 41

Number of students van can carry = 11

Number of students bus can carry = 41

6 0
3 years ago
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Galina-37 [17]
I think the answer would be three because if you multiply all of the numbers together you get 30.
3 0
3 years ago
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Equity is same as equility it is for making students fools.

Step-by-step explanation:

Equity=Equality

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3 years ago
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