Answer:
part A: expression 1: 6(8m+2)
expression 2: 6m+12+42m
Part B: 6(m+2+7m)= 6(8m+2)
combine like terms is 6(m+2+7m), so it is 6(2+8m) or 6(8m+2)
6(8m+2)= 6(8m+2)
Part C: 6m+12+42m=6(m+2+7m)
m=0
6(0+2+7(0))=6(0)+12+42(0)
6(2)= 12
12=12
Answer:
B
Step-by-step explanation:
Answer: B
Step-by-step explanation:
Point G cannot be a centroid because GE is wider that JG or JG is shorter than GE. So in this diagram GE is wider than JG with 10 cm and 5 cm respectively based on this information Point G cannot be a centroid of triangle HJK. So the answer is point G cannot be a centroid because JG is shorter than GE.
Answer:
54 Pounds
Step-by-step explanation:
We know that they start off with 67.5 pounds of sugar and they need to reduce it by 20%. We also know from the problem that we want to know the MAXIMUM amount of sugar consumed by each track member.
The typical high school student consumes about 67.5 pounds of sugar per year. That is our first piece of the problem
67.5
We now know that 20% of it needs to be reduced. This means that we can multiply it by 0.8 because that is 20% less than 100% of the sugar.
67.5 x 0.8
This leads the answer to be 54 Pounds
Hope this helped :D
