A 20 kg sled is pulled up a 10m tall hill. What work is done against gravity?
1 answer:
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Answer:
h = 1.22 m
Explanation:
Given:
Pressure in the vein = 12200 Pa
Specific gravity of the liquid = 1.02
now,
the pressure due to a fluid is given as:
P = pgh
where,
P is the pressure,
ρ is the density of fluid = specific gravity x density of water = 1.02 x 1000 kg/m³
ρ = 1020 kg/m³
g is the acceleration due to the gravity = 9.81m/s²
h is the height
thus,
h = P/pg =
Answer:
2) a_y= -g 3) vₓ=constant v_y = v_{oy} - g t, 4) vₓ = v₀ₓ - ax t
5) changes the horizontal speed, should change range
7) changes the vertical speed change the maximum height
Explanation:
1) After reading your long writing, we are going to solve the exercise, in the attachment you can see the different vectors.
2) The acceleration vectors are vertical and directed downwards due to the attraction of the Earth (gravity force) this force is constant, on the x axis there is no acceleration
3) the velocity vectors on the x-axis are constant because there are no relationships and the y-axis changes value according to the expression
v_y = v_{oy} - gt
at the point of maximum height, vy = 0 is equal to the maximum height
4) For someone to change the horizontal acceleration we must assume a friction with the air, in this case they relate it would be in the opposite direction to the horizontal speed
In the graph it would be directed to the left, therefore the velocity would be
vₓ = v₀ₓ - ax t
5 and 6) If someone changes the horizontal speed, they should change the range of the shot for greater horizontal speed, the rock goes further.
the equations of motion are
x = v₀ₓ t
y = v_{oy} t - ½ g t²
7) If someone changes the vertical speed change the maximum height, but not the scope of the shot, for higher speed higher maximum height,
the equations of motion are the same.
