Answer:
Id = 1/2 Md * R^2 = 1/2 * .1 * .1^2 = .0005 kg m^2 inertia of disk
Ib = Mb * R^2 = .02 * .1^2 = .0002 kg m^2 inertia of bug at edge
(Id + Ib) w1 = Id w2 conservation of angular momentum
w2 = .0007 / .0005 * 10 = 14 /sec angular speed with bug at center
KE1 = 1/2 I1 * w1^2 = 1/2 * .0007 * 10^2 = .035 kg m^2 / s^2
KE2 = 1/2 * I2 w2*2 = (.0005 / 2 ) ^ 14^2 = .049 kg m^2 / s^2
The bug has to exert radial force on the disk to maintain its
centripetal acceleration. As the bug crawls to the center of the disk it
does work against this centripetal force which appears as an increase
of rotational energy of the disk. As the the bug crawls back to the edge
of the disk, the disk does work on the bug and loses KE.
Answer:
Passive range of motion can be defined as what is achieved when an outside force, such as a therapist, causes movement of a joint. It is usually the maximum range of motion. Active range of motion is what can be achieved when opposing muscles contract and relax, resulting in joint movement