Complete question is;
A ski jumper travels down a slope and leaves the ski track moving in the horizontal direction with a speed of 24 m/s. The landing incline below her falls off with a slope of θ = 59◦ . The acceleration of gravity is 9.8 m/s².
What is the magnitude of the relative angle φ with which the ski jumper hits the slope? Answer in units of ◦
Answer:
14.08°
Explanation:
The time covered will be given by the formula;
t = (2V_x•tan θ)/g
t = (2 × 24 × tan 59)/9.8
t = 8.152 s
Now, the slope of the flight path at the point of impact will be given by the formula;
tan α = V_y/V_x
We are given V_x = 24 m/s
V_y will be gotten from the formula;
v = gt
Thus;
V_y = gt
V_y = 9.8 × (8.152) = 78.89 m/s
Thus;
tan α = 78.89/24
tan α = 3.2871
α = tan^(-1) 3.2871
α = 73.08°
Thus ;
Relative angle φ = α - θ = 73.08 - 59 = 14.08°
Answer:
50°
Explanation:
Projectiles launched at complementary angles have the same range.
Answer:
655 nm
Explanation:
When the intereference is destructive then the thickness, d of antireflective film coating one side is given by
2d=w/2n
Where w is wavelength and n is the reflective index of the film
Making w the subject of formula then
w=4nd
Substituting 1.25 for n and 131 nm for d then the wavelength will be
w=4*1.25*131=655 nm
Therefore, the wavelength is equivalent to 655 nm
Answer:
Electrons
<h2>What are electrons?</h2>
An elementary particle that is a fundamental constituent of matter, having a negative charge of 1.602 × 10- 19 coulombs, a mass of 9.108 × 10 - 31 kilograms, and spin of 1/2, and existing independently or as the component outside the nucleus of an atom. It can also be defined as a unit of charge equal to the charge of one electron.
Explanation:
because the moon has less mass than earth, the force due to gravity at the lunar surface is only about 1/6 that on earthso,the weight of a body on earth is 6×5N =30N