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CaHeK987 [17]
4 years ago
15

The Top Thrill Dragster stratacoaster at Cedar Point Amusement Park in Ohio uses a hydraulic launching system to accelerate ride

rs from 0 to 54 m/s (120 mi/hr) in 3.8 seconds before climbing a completely vertical 420-foot hill. Determine the net force required to accelerate an 86-kg man.
Physics
1 answer:
Mariulka [41]4 years ago
3 0

Answer:

A. 1222,10 N

Explanation:

First, we determine the value of the acceleration that the hydraulic launching system must guarantee. Let’s remember that the definition of acceleration is the rate of change of velocity with respect to time. Therefore:

a_hyd = ∆v/∆t = (54 m/s-0)/(3,8 s-0) = 14,21 m/s^2  

According to Newton’s second law:

∑F_net = m*a = 86 kg*14,21 m/s^2 = 1222,10 N

So, the net force required to accelerate an 86-kg man is 1222,10 N

Have a nice day! :D

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The mass of the bicycle and rider is 60 kg and the total area of the tyres in contact with
AleksAgata [21]

Answer:

a little

Explanation:

First of all, it's not how you spell "tyres", it is tires.

Second of all, you already know the Mass so what you need to find out now is  contact the road. You Know that your number and letter are squared so that would turn into 6m x 2.4. Then you do the math do continue on to finish it. Have a great day!! Good luck with the answer!!

3 0
3 years ago
Why does a magnet attract a steel nail
SVEN [57.7K]

Answer:

The nail will stick to the bar magnet because it will become magnetized, and it's metal. The presence of the nearby north pole rearranges the magnetic domains inside the steel so that their south poles all point toward the north pole of the permanent magnet. As a result, the other end of the nail becomes a north pole.Magnets attract iron due to the influence of their magnetic field upon the iron. ... When exposed to the magnetic field, the atoms begin to align their electrons with the flow of the magnetic field, which makes the iron magnetized as well. This, in turn, creates an attraction between the two magnetized objects.

7 0
3 years ago
If the ultimate shear strength of steel is taken to be 3.00 109 Pa, what force is required to punch through a steel plate 1.60 c
photoshop1234 [79]

Answer:

Explanation:

Given

Ultimate shear strength \tau =3\times 10^9\ Pa

thickness of steel Plate t=1.60\ cm

Cross-sectional A=1.20\times 10^2\ cm^2

suppose d is the diameter of cross-section

\frac{\pi }{4}d^2=1.20\times 10^2

d=12.359\ cm

Shear area of circular cross-section

A_s=\pi dt

A_s=\pi \times 12.359\times 1.6

A_s=62.13\ cm^2

Shear Force F_s=A_s\times \tau

F_s=62.13\times 10^2\times 3000

F_s=18.639\ MN  

6 0
3 years ago
We are given the description of an enclosure that has fencing on 3 sides and can use 3,056 yards of fencing. We are to find the
shusha [124]

Answer:

The sum of the lengths of the sides is 2292 yards and the sum of the lengths of the triangle is 3056 yards

Explanation:

Since y represents the length of fence that is opposite (parallel) to the river and x represent the length of fence perpendicular to the river.

Therefore since we can use 3,056 yards of fencing

Side perpendicular to the river = x and,

Side opposite to the river = y = 3056 - 2x

The area of the rectangle formed (A) = Perpendicular side × Parallel side

∴ A = x(3056 - 2x) = 3056x - 2x²

A = 3056x - 2x²

To maximize the area, A' (dA/dx) = 0

∴ A' = 3056 - 4x = 0

3056 - 4x = 0

4x = 3056

x = 764 yards

y =  3056 - 2x = 3056 - 2(764) = 1528 yards.

Side perpendicular to the river = 764 yards and,

Side opposite to the river = 1528 yards

The sum of the lengths of the sides = 764 + 1528 = 2292 yard and the sum of the lengths of the triangle = 764 + 764 + 1528 = 3056 yards

5 0
3 years ago
What is the total resistance of the circuit? (must include unit - ohms) I WILL GIVE BRAINLIEST!
ICE Princess25 [194]

Answer: 4 ohms

Explanation:

For parallel connection we use this formula

R=equivalent resistance

R1=24 ohms

R2=8 ohms

R3=12 ohms

1/R=1/R1 + 1/R2 + 1/R3

1/R=1/24 + 1/8 + 1/12

1/R=(1x1+3x1+2x1) ➗ 24

Cross multiplying we get

24x1=(1x1+3x1+2x1) x R

24=(1+3+2) x R

24=6xR

Divide both sides by 6

24 ➗ 6=6xR ➗ 6

4=R

R=4 ohms

8 0
4 years ago
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