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CaHeK987 [17]
4 years ago
15

The Top Thrill Dragster stratacoaster at Cedar Point Amusement Park in Ohio uses a hydraulic launching system to accelerate ride

rs from 0 to 54 m/s (120 mi/hr) in 3.8 seconds before climbing a completely vertical 420-foot hill. Determine the net force required to accelerate an 86-kg man.
Physics
1 answer:
Mariulka [41]4 years ago
3 0

Answer:

A. 1222,10 N

Explanation:

First, we determine the value of the acceleration that the hydraulic launching system must guarantee. Let’s remember that the definition of acceleration is the rate of change of velocity with respect to time. Therefore:

a_hyd = ∆v/∆t = (54 m/s-0)/(3,8 s-0) = 14,21 m/s^2  

According to Newton’s second law:

∑F_net = m*a = 86 kg*14,21 m/s^2 = 1222,10 N

So, the net force required to accelerate an 86-kg man is 1222,10 N

Have a nice day! :D

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5 0
4 years ago
what is the voltage in mv across an 5.5 nm thick membrane if the electric field strength across it is 5.75 mv/m? you may assume
inn [45]

Answer:

V = 31.62 m V

Explanation:

Given,

Voltage across thick membrane = ?

Thickness of the membrane, d = 5.5 n m

Electric field = 5.75 M V/m

we know

E = \dfrac{V}{d}

   V = E d

   V = 5.75 x 10⁶ x 5.5 x 10⁻⁹

   V = 31.62 x 10⁻³ V

   V = 31.62 m V

Hence, The Voltage across the membrane is equal to 31.62 m V.

3 0
4 years ago
Tarzan, who weighs 849 N, swings from a cliff at the end of a 18.0 m vine that hangs from a high tree limb and initially makes a
loris [4]

Answer:

Part a)

T = 342.5 \hat i + 675\hat j

Part b)

F_{net} = 342.5\hat i - 174\hat j

Part c)

F = 384.2 N

Part d)

\theta = 333 degree

Part e)

a = 4.4 m/s^2

Part f)

\theta = 333 degree

Explanation:

Part a)

Magnitude of tension force is given as

T = 757 N at 26.9 degree with vertical

T = 757 sin26.9 \hat i + 757 cos26.9 \hat j

T = 342.5 \hat i + 675\hat j

Part b)

Net force on Tarzen is given as

F_{net} = T + F_g

F_{net} = 342.5 \hat i + 675\hat j - 849 \hat j

F_{net} = 342.5\hat i - 174\hat j

Part c)

magnitude of the force is given as

F = \sqrt{F_x^2 + F_y^2}

F = \sqrt{342.5^2 + 174^2}

F = 384.2 N

Part d)

Direction of the force is given as

tan\theta = \frac{F_y}{F_x}

tan\theta = \frac{-174}{342.5}

\theta = 333 degree

Part e)

Magnitude of the acceleration

a = \frac{F}{m}

m = \frac{849}{9.81} = 86.5 kg

tex]a = \frac{384.2}{86.5}[/tex]

a = 4.4 m/s^2

Part f)

Direction of acceleration is same as the direction of the force

\theta = 333 degree

6 0
3 years ago
Mass refers to the gravitational force on the matter in contact with the surface of a planet
Arte-miy333 [17]

Answer: Yes and no.

Explanation: Mass is the amount of matter in an object, whereas weight is the force exerted on an object by gravity. Objects on the surface of the earth have weight, although sometimes the weight is difficult to measure.

8 0
4 years ago
Which of the following are not likely to form bonds?
Zanzabum
The answer is NEON Atoms
5 0
3 years ago
Read 2 more answers
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