suppose the three sides are 2x, 6x, and 7x in length.
2x+6x+7x+195
15x=195
x=195/15=13
the longest side is 7*13=91 meters
8500 x 6.5 x 10 + 8500 =
8500 x 6.5 + 8500 =
8500 x 6.5/100 + 8500 =
8500 x 13/20 + 8500 =
110500/20 + 8500 =
5525 + 8500 =
14025
<span>Debra spent a total of 49 hours doing these two assignments. The answer is calculated as the sum of 15 + 34 = 49.</span>
Let P be the last point in the triangle you have drawn from AB.. It is isosceles and rectangle hence AB^2=2BP^2 hence AP=BP=sqrt(2).
Let Q be the last point in the triangle you have drawn from CD. By the same reasoning, CQ=DQ=sqrt(2)
What is more, AD=AP+PQ+QD=2sqrt(2)+1
Answer:
64π
Step-by-step explanation:
C = 2πr
C = 2π(32)
C = 64π
