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-Dominant- [34]
3 years ago
5

Classify the random variables below according to whether they are discrete or continuous. a. The floor area of a kitchen. b. The

number of bacteria in a particular cubic centimeter of drinking water. c. The dollar amount of the change in your pocket. d. The barometric pressure at a given location. e. The difference in reaction time to the same stimulus before and after training
Mathematics
1 answer:
kherson [118]3 years ago
3 0

Answer:

A. Continuous, B. Discrete, C. Continuous, D. Continuous, E. Continuous.

Step-by-step explanation:

A. Area is a continuous unit. Then, the floor area of a kitchen is a continuous random variable.

B. Quantity is a discrete unit. Then, the number of bacteria in a particular cubic centimeter of drinking water is a discrete random variable.

C. The money amount is a continuous unit. Then, the dollar amount of the change in my pocket is a continuous random variable.

D. The pressure is a continuous unit. Then, the barometric pressure at a given location is a continuous random variable.

E. Time is a continuous unit. Then, the difference in reaction time to the same stimulus before and after training is a continuous random variable.

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Which of the following expressions represents the GCF of 91x 2 y and 104xy 3?
zlopas [31]
The greatest common factor is found by finding the product of common primes.

91=7*13, 104=2*2*2*13  so the gcf of 91 and 104 is 13.  Since the highest power of x and y in both terms is 1, the hcf for the variables is just xy

13xy
6 0
3 years ago
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Mateo has 31/2 pounds of apples he uses 3/4 of a pound of apples for each batch of applesauce how many batches of applesauce can
andreyandreev [35.5K]

Answer:

20 2/3

Step-by-step explanation:

8 0
3 years ago
In rectangle abcd measure of angle d =(3x+15) measure b =(6x-42) find measure of angle a
slava [35]
5) So for parallelogram ABCD, ∠B ≅ ∠D, and ∠A ≅ ∠C. Further, ∠B and ∠A are supplementary (i.e., their sum is 180°), and ∠D and ∠C are also supplementary.
So, we have that m∠B = m∠D. Therefore, 
6x-42=3x+15\\3x=57\\x=19

Now, let's substitute for x back into the expression for either ∠B or ∠D to find it's angle measure.
m∠B = 6(19)-42=72
Now, remember that ∠B or ∠D are supplements of ∠A. 
So, m∠B + m∠A = 180°.
That means m∠A = 180° – 72° = 108°.
That seems reasonable, because A appears to be an obtuse angle.
6 0
3 years ago
How can you check that this answer is correct? 5,244 = 6= 874​
nignag [31]

I think you meant 5,244 ÷ 6 = 874.

Answer/Step-by-step explanation:

We can check if this 5,244 ÷ 6 = 874 is correct by doing it opposite.

Since it 5,244 divide 6 we can do 874 x 6.

  \left[8   7   4] \\

×    [6]

======

+ 5244

=======

5244

Hence, this answer is correct.

[RevyBreeze]

3 0
2 years ago
16. A telemarketer makes six phone calls per hour and is able to make a sale on 30% of these contacts. During the next two hours
Reika [66]

Answer:

a) 23.11% probability of making exactly four sales.

b) 1.38% probability of making no sales.

c) 16.78% probability of making exactly two sales.

d) The mean number of sales in the two-hour period is 3.6.

Step-by-step explanation:

For each phone call, there are only two possible outcomes. Either a sale is made, or it is not. The probability of a sale being made in a call is independent from other calls. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A telemarketer makes six phone calls per hour and is able to make a sale on 30% of these contacts. During the next two hours, find:

Six calls per hour, 2 hours. So

n = 2*6 = 12

Sale on 30% of these calls, so p = 0.3

a. The probability of making exactly four sales.

This is P(X = 4).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 4) = C_{12,4}.(0.3)^{4}.(0.7)^{8} = 0.2311

23.11% probability of making exactly four sales.

b. The probability of making no sales.

This is P(X = 0).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{12,0}.(0.3)^{0}.(0.7)^{12} = 0.0138

1.38% probability of making no sales.

c. The probability of making exactly two sales.

This is P(X = 2).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{12,2}.(0.3)^{2}.(0.7)^{10} = 0.1678

16.78% probability of making exactly two sales.

d. The mean number of sales in the two-hour period.

The mean of the binomia distribution is

E(X) = np

So

E(X) = 12*0.3 = 3.6

The mean number of sales in the two-hour period is 3.6.

4 0
3 years ago
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