Write a recursive formula for the sequence 1, 5, 9, 13

Mathematics

1 answer:

11Alexandr11 [23.1K]2 years ago

5 0

Answer:

$\bold{a(n) \ = \ a(n \ + \ 1) \ + \ 4}$

Explanation:

Sequence: 1, 5, 9, 13

Add(ing) 4 every time

$\bold{a(1) \ = \ 1}$

$\bold{\bold{a(n) \ = \ a(n \ + \ 1) \ + \ 4}}$

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A coin is tossed twice. Let H represents heads, T represents tails, and the combination of the two letters represent the outcome

denis23 [38]

Answer:

{HH, HT, TH, TT}

Step-by-step explanation:

The set of all possible outcomes in tossing a coin twice is;

{HH, HT, TH, TT}

In the first toss the coin may land Heads. In the second toss the coin may land Heads or Tails. This can be represented as;

HH, HT

Heads in the first and second tosses. Heads in the first toss followed by a Tail in the second toss.

In the first toss the coin is also likely to land Tails. In the second toss the coin may land Heads or Tails. This can be represented as;

TH, TT

Tails in the first toss followed by a Head in the second toss. Tails in the first and second tosses.

Combining these two possibilities will give us the set of all possible outcomes in tossing a coin twice is;

{HH, HT, TH, TT}

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What is the abscissa of the midpoint of the line segment whose endpoints are (5√2,2√3) and (√2,2√3)

xxMikexx [17]

Let
A------> (5√2,2√3)
B------> (√2,2√3)

we know that
the abscissa and the ordinate are respectively the first and second coordinate of a point in a coordinate system
the abscissa is the coordinate x

step 1
find the midpoint
ABx------> midpoint AB in the coordinate x
ABy------> midpoint AB in the coordinate y

ABx=[5√2+√2]/2------> 6√2/2-----> 3√2
ABy=[2√3+2√3]/2------> 4√3/2-----> 2√3

the midpoint AB is (3√2,2√3)

the answer is
the abscissa of the midpoint of the line segment is 3√2

see the attached figure