A large number of disease-free individuals were enrolled in a study
1 answer:
Answer:
a,Answer: Type I right censoring, censoring time = 60.
b.This is called an Interval censoring,
c.this is called Random censoring because the year in consideration was chosen at random, censoring time = 61.
d.The observations are left truncated respectively at age 30, 40, 50 and 42.
e.
Explanation:
a) A healthy individual, enrolled in the study at age 30, never developed
breast cancer during the study.
Answer: Type I censoring, censoring time = 60.
(b) A healthy individual, enrolled in the study at age 40, was diagnosed
with breast cancer at the fifth exam after enrollment (i.e., the disease
started sometime between 12 and 15 years after enrollment).
THis is called an Interval censoring,
if the clinical exams is conducted every three years , then 3*4=12, and 3*5=15
add this to 40 years respectively, we have
censoring time = (52, 55]
c) A healthy individual, enrolled in the study at age 50, died from a
cause unrelated to the disease (i.e., not diagnosed with breast cancer
at any time during the study) at age 61.
this is called Random censoring because the year in consideration was chosen at random, censoring time = 61.
(d) An individual, enrolled in the study at age 42, moved away from
the community at age 55 and was never diagnosed with breast cancer
during the period of observation.
Random censoring, censoring time = 55.
The observations are left truncated respectively at age 30, 40, 50 and 42.
e. Confining your attention to the four individuals described above,
write down the likelihood for this portion of the study.
the above represent the likelihood
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Answer:
The correct answer would be:
- Genotype ratio: 1 (PP) : 2 (Pp) : 1 (pp)
- Phenotypic ratio: 3 (polka-dot tails) : solid colored tail
The genotype of both parents is Pp (heterozygous).
Thus, both the parent would produce two types of gametes which are P and p.
The cross would result in the production of offspring with three types of genotype PP, Pp, and pp in 1:2:1.
Offspring with PP and Pp will have a polka-dotted tail as it is the dominant trait.
Thus, the phenotype ratio would be 3 (polka-dotted tail) : 1 (solid colored tail).
