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3 years ago

What do you call the process of finding the magnitude of fy

Physics

2 answers:

vlada-n [284]3 years ago

4 0

Answer:

The process of finding the magnitude of Fy is called vector resolution.

Explanation:

Given a vector with a magnitude equals to F which forms an angle equals to θ with the x-axis, then it can be decomposed into two smaller vectors (Fx and Fy) as follows:

Fx = F*cosθ (placed on the x-axis)

Fy = F*sinθ (placed on the y-axis)

This process is called vector resolution.

MAVERICK [17]3 years ago

3 0

Answer - vector resolution

Any vector suppose f if lies at some angle, then

fy = F x cos or sin (theta)

and fx = F x cos or sin (theta)

Process of finding the value of component of any vector quantity is called Vector Resolution.

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Complete Question

A ball having mass 2 kg is connected by a string of length 2 m to a pivot point and held in place in a vertical position. A constant wind force of magnitude 13.2 N blows from left to right. Pivot Pivot F F (a) (b) H m m L L If the mass is released from the vertical position, what maximum height above its initial position will it attain? Assume that the string does not break in the process. The acceleration of gravity is 9.8 m/s 2 . Answer in units of m.What will be the equilibrium height of the mass?

Answer:

$H_m=1.65m$

$H_E=1.16307m$

Explanation:

From the question we are told that

Mass of ball $M=2kg$

Length of string $L= 2m$

Wind force $F=13.2N$

Generally the equation for $\angle \theta$ is mathematically given as

$tan\theta=\frac{F}{mg}$

$\theta=tan^-^1\frac{F}{mg}$

$\theta=tan^-^1\frac{13.2}{2*2}$

$\theta=73.14\textdegree$

Max angle = $2*\theta= 2*73.14=>146.28\textdegree$

Generally the equation for max Height $H_m$ is mathematically given as

$H_m=L(1-cos146.28)$

$H_m=0.9(1+0.8318)$

$H_m=1.65m$

Generally the equation for Equilibrium Height $H_E$ is mathematically given as

$H_E=L(1-cos73.14)$

$H_E=0.9(1+0.2923)$

$H_E=1.16307m$

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